如何从jqgrid自定义按钮获取json响应。这是我的代码
URL url = new URL("some url for downloading a file");
BufferedInputStream bis = new BufferedInputStream(url.openStream());
FileOutputStream fis = new FileOutputStream(file);
int size = 65536;
byte[] buffer = new byte[size];
int count;
while ((count = bis.read(buffer, 0, size)) != -1) {
fis.write(buffer, 0, count);
}
fis.close();
bis.close();
答案 0 :(得分:0)
您需要更换
...
window.location.href = "/Controller/Action";
...
与ajax一样
$.ajax({
url : "/Controller/Action",
dataType : "json",
success : function(response, status, jqXHR) {
// response is your json data
}
});