在同一个数组中只有多个相同的字符串名称？

Question

我遇到的问题如下：我创建了10个表示船舶停靠空间的行输出。

但码头可以容纳两种尺寸的船;货物和集装箱。行由5个小型和5个中型组成。货船（小）可以在任何可用空间停泊。集装箱船（中型）可停泊在中等空间，但不能停泊在狭小的空间内。

因此，如果我输入shipName和Container，它会搜索数组，确保少于5个Container，这样它就可以停靠，即保存在数组中。你能帮我吗？ 这是我的dock方法：

import java.util.*;

public class Main {

static Scanner scan = new Scanner(System.in);
private static Ship[] dock1 = new Ship[10];

public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);


    while(true) {

        System.out.println("Choose an option: 1-3");
        System.out.println("1. Dock");
        System.out.println("2. Undock");
        System.out.println("3. Status");

        int menu = scan.nextInt();
            switch (menu) {
                case 1:
                    System.out.println("1. Dock");
                    dock();
                    break;
                case 2:
                    System.out.println("2. Undock");
                    undock();
                    break;
                case 3:
                    System.out.println("3. Status");
                    printArray();
                    break;
                case 4:
                    System.out.println("4. Exit");
                    System.exit(0);
                default:
                    System.out.println("No such option");
                    break;
            }
        }
}

public static void dock() {

    int dockCapacity = 0;

    System.out.println("Enter ship's name: ");
    String name = scan.nextLine();

    System.out.println("Enter ship's size: ");
    String size = scan.nextLine();

    System.out.println("Enter the ships dock:");
    //search for 5 small 3 med 2 large

 //    if what they entered equals shipSize more than 5 than cannot dock.
    for(int i = 1; i < dock1.length; i++) {
        if (dock1[i].getShipSize().equals(size)) {
            System.out.print(dock1[i].getShipSize());
        }
        else {
            System.out.println("Couldn't dock");
        }
    }
    //Check if the dock number is valid
    int i = Integer.valueOf(scan.nextLine());
    if (i >= 0 && i < 10 && dock1[i] == null){
        //Add ship to the dock
        dock1[i] = new Ship(name, size);
        System.out.println("Ship has been docked");
    }
    else{
        System.out.println("Couldn't dock");
    }
   // printArray();
}

public static void undock(){

    System.out.println("Status of ships: ");
    printArray();
    System.out.println("Enter ship's name to undock: ");
    String name = scan.nextLine();
    for(int i = 1; i < dock1.length; i++){
    if(dock1[i] != null && dock1[i].getShipName().equals(name)){
        dock1[i] = null;
        System.out.println("Ship removed");
        break;
    }
    else{
        System.out.println("Ship not docked here");
    }
    }

}

public static void printArray() {

    System.out.println("Docks:");

    for(int i = 0; i < dock1.length; i++)
    {
        if(dock1[i] == null)
        {
            System.out.println("Dock " + i + " is empty");
        }
        else
        {
            System.out.println("Dock " + i + ": " + dock1[i].getShipName() + " " + dock1[i].getShipSize());
        }
    }
}
}

船舶类

public class Ship {

private String shipName;
private  String shipSize;

public String getShipName() {
    return shipName;
}

public void setShipName(String shipName) {
    this.shipName = shipName;
}

public String getShipSize() {
    return shipSize;
}

public void setShipSize(String shipSize) {
    this.shipSize = shipSize;
}

public Ship(String shipName, String shipSize) {
    this.shipName = shipName;
    this.shipSize = shipSize;
}
}

Answer 1

我建议你像这样更改Ship类。它添加了ShipSize枚举，使得从字符串解析船舶尺寸和比较船舶尺寸变得更加容易。另外，我添加了define([ 'jquery', 'jquery/ui' ], function($) { "use strict"; $.widget('NameSpace.widget', { options: { triggerEvent: 'change', controller: 'frontName/query/custom', qty: '[data-role="cart-item-qty"]', itemId: '.action.action-edit' }, _create: function() { this._bind(); }, _bind: function() { var self = this; self._ajaxSubmit(); }, _ajaxSubmit: function() { jQuery(this.options.qty).on('change', function () { var that = this; // here we need to refer to the context of jQuery var url = domine + 'NameSpace_widget/query/custom'; jQuery.ajax({ url: url, type: 'post', dataType: 'json', data: //your data, success: function(res) { // your code } }); }); }, _updateOrderHandler: function () { $(this).trigger('change'); } }); return $.NameSpace.widget; }); 和isCargo方法。

isContainer

我还修改了你的主类，所以它可以做你想要的。我添加了一些解析和检查数字，为扩展添加了一个初始化方法。

import java.util.Arrays;

public class Ship {

    private String shipName;
    private ShipSize shipSize;
    public Ship(String shipName, ShipSize shipSize) {
        this.shipName = shipName;
        this.shipSize = shipSize;
    }

    public String getShipName() {
        return shipName;
    }

    public void setShipName(String shipName) {
        this.shipName = shipName;
    }

    public ShipSize getShipSize() {
        return shipSize;
    }

    public void setShipSize(ShipSize shipSize) {
        this.shipSize = shipSize;
    }

    public boolean isCargo() {
        return shipSize == ShipSize.CARGO;
    }

    public boolean isContainer() {
        return shipSize == ShipSize.CONTAINER;
    }

    public enum ShipSize {
        CARGO,
        CONTAINER;

        public static ShipSize of(String size) {
            return Arrays.stream(ShipSize.values()).filter(enumSize -> enumSize.name().equalsIgnoreCase(size)).findAny().orElse(null);
        }
    }
}

我还添加了一个Dock类。它工作正常。

import java.util.*;

public class Main {

    static Scanner scan = new Scanner(System.in);
    private static Dock[] dock1 = new Dock[10];

    public static void main(String[] args) {

        initializeDock();

        Scanner scan = new Scanner(System.in);


        while(true) {

            System.out.println("Choose an option: 1-3");
            System.out.println("1. Dock");
            System.out.println("2. Undock");
            System.out.println("3. Status");

            int menu = scan.nextInt();
            switch (menu) {
                case 1:
                    System.out.println("1. Dock");
                    dock();
                    break;
                case 2:
                    System.out.println("2. Undock");
                    undock();
                    break;
                case 3:
                    System.out.println("3. Status");
                    printArray();
                    break;
                case 4:
                    System.out.println("4. Exit");
                    System.exit(0);
                default:
                    System.out.println("No such option");
                    break;
            }
        }
    }

    private static void initializeDock() {
        for (int i = 0; i < 5; i++) {
            dock1[i] = new Dock(Ship.ShipSize.CARGO);
        }
        for (int i = 5; i < 10; i++) {
            dock1[i] = new Dock(Ship.ShipSize.CONTAINER);
        }
    }

    public static void dock() {

        int dockCapacity = 0;

        System.out.println("Enter ship's name: ");
        String name = scan.nextLine();

        Ship.ShipSize size = null;
        while(size == null) {
            System.out.println("Enter ship's size: ");
            String stringSize = scan.nextLine();
            size = Ship.ShipSize.of(stringSize);
            if (size == null) {
                System.out.println("Could not read ship size. Only cargo and container are allowed.");
            }
        }

        // check that ship fits into any dock
        if (size == Ship.ShipSize.CONTAINER) {
            long numberOfContainerShips = Arrays.stream(dock1).map(Dock::getDockedShip).filter(Objects::nonNull).filter(Ship::isContainer).count();
            if (numberOfContainerShips >= 5) {
                System.out.println("No place for a ship that large. Aborting.");
                return;
            }
        }

        System.out.println("Enter the ships dock:");
        Integer dockNumber = null;
        while(dockNumber == null) {
            dockNumber = scan.nextInt();
            if (dockNumber < 0 || dockNumber > dock1.length - 1) {
                System.out.println("Illegal dock number. Only numbers between 0 and " + dock1.length + " are allowed.");
                dockNumber = null;
            }
        }

        Dock dock = dock1[dockNumber];
        if (dock.getDockedShip() != null) {
            System.out.println("Dock reserved - couldn't dock");
            return;
        }
        if (dock.getSupportedSize() == Ship.ShipSize.CARGO && size == Ship.ShipSize.CONTAINER) {
            System.out.println("Dock too small - couldn't dock");
            return;
        }

        dock.setDockedShip(new Ship(name, size));
    }

    public static void undock(){

        System.out.println("Status of ships: ");
        printArray();
        System.out.println("Enter ship's name to undock: ");
        String name = scan.nextLine();
        for(int i = 1; i < dock1.length; i++){
            if(dock1[i].getDockedShip() != null && dock1[i].getDockedShip().getShipName().equals(name)){
                dock1[i] = null;
                System.out.println("Ship removed");
                break;
            }
            else{
                System.out.println("Ship not docked here");
            }
        }

    }

    public static void printArray() {

        System.out.println("Docks:");

        for(int i = 0; i < dock1.length; i++)
        {
            if(dock1[i].getDockedShip() == null)
            {
                System.out.println("Dock " + i + " is empty. Size: " + dock1[i].getSupportedSize().name().toLowerCase());
            }
            else
            {
                System.out.println("Dock " + i + ": " + dock1[i].getDockedShip().getShipName() + " " + dock1[i].getDockedShip().getShipSize().name().toLowerCase());
            }
        }
    }
}