Question

我想改变最后的＆＃34; S＆＃34;数组值中的字母。我尝试了很多方法，但仍然无法工作。

这是我的代码（）：

<?php
$array = array ("romeo/echos/julion/1991s/1992.jpg",
                "romeo/echos/julion/1257s/1258.jpg",
                "romeo/echos/julion/1996s/1965.jpg",
);

foreach ($array as $key => $value) {
    if ($key == "romeo/echos/julion/'.*?'s/'.*?'.jpg") 
         $value="romeo/echos/julion/'.*?'l/'.*?'.jpg";
}

print_r($value);
?>

我希望价值看起来像这样：

Array ( [0] => romeo/echos/julion/1991l/1992.jpg 
        [1] => romeo/echos/julion/1257l/1258.jpg 
        [2] => romeo/echos/julion/1996l/1965.jpg
      )

Answer 1

$value是数组元素的副本，因此分配给它不会修改数组。如果使用引用变量，它将更新数组。

另外，您没有正确测试该值。首先，当您使用==来测试正则表达式模式时，您正在使用preg_match()。您正在测试$key而非$value（密钥只是索引0，1，2等。）

foreach ($array as &$value) {
    if (preg_match('#(romeo/echos/julion/.*?)s(/.*?.jpg)#', $value, $match)) {
        $value = $match[1] . "l" . $match[2];
    }
}

Answer 2

我测试了以下内容，它提供了您想要的确切输出。

$array = array("romeo/echos/julion/1991s/1992.jpg",
            "romeo/echos/julion/1257s/1258.jpg",
            "romeo/echos/julion/1996s/1965.jpg");

$replace = str_replace("s/1", "l/1", $array);
    print_r($replace);  
}

输出：

Array ( 
    [0] => romeo/echos/julion/1991l/1992.jpg 
    [1] => romeo/echos/julion/1257l/1258.jpg 
    [2] => romeo/echos/julion/1996l/1965.jpg 
)

Answer 3

使用str_replace()

  <?php
    $array = array ("romeo/echos/julion/1991s/1992.jpg",
                    "romeo/echos/julion/1257s/1258.jpg",
                    "romeo/echos/julion/1996s/1965.jpg",
    );

    foreach ($array as $key => $value) {

      $arr[]=str_replace('s/1','l/1',$value);
    }

    print_r($arr);
    ?>

输出：

Array ( [0] => romeo/echos/julion/1991l/1992.jpg [1] => romeo/echos/julion/1257l/1258.jpg [2] => romeo/echos/julion/1996l/1965.jpg )

替换数组值PHP

3 个答案: