Question

这是我的代码。我正在尝试使用JSP和MYSQL向表中添加值。表和数据库的名称是正确的。

＆＃13;

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<%@ page import ="java.sql.*" %>
<%@ page import ="javax.sql.*" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Inserting Data from form</title>
</head>
<body>

      <h1> Insert a Record</h1>
      <form method="post" action="insertrecord.jsp">
      <table>
      <tr>
      <td>
       <input type="text" name="uname">
      </td>
      <td>
      <input type="password" name="upass">
      </td>
      <tr>
      <tr>
      <td><input type="submit" name="submit" value ="submit"></td>
      </tr>
      </table>
      </form>
 <%
 
 String sub = request.getParameter("submit");
 if(sub!=null)
 {
 String uname=request.getParameter("uname");
 String password = request.getParameter("upass");
 if(uname!=null && password!=null)
 {
	 try
	 {
      Connection con;
      Class.forName("com.mysql.jdbc.Driver").newInstance();
      con = DriverManager.getConnection("jdbc:mysql://localhost:3306/demo","root","");
      Statement stmt = con.createStatement();
      int i = stmt.executeUpdate("insert into user values ('"+uname+"','"+password+"')");
      out.println("Record Inserted Successfully");
      stmt.close();
      con.close();
	 }
	 catch(SQLException e)
	 {
		 out.println(e.getMessage());
	 }
 }
 }
 %>  
   
</body>
</html>

＆＃13;

当我点击提交时。我收到此错误： HTTP状态404 - 未找到

输入状态报告

消息/something/insertrecord.jsp

描述源服务器没有找到目标资源的当前表示，或者不愿意透露该目标资源是否存在。

Apache Tomcat / 9.0.5

HTTP状态404 - 未找到Tomcat

0 个答案: