Question

我是Spring DataJPA + REST项目的新手，我正在尝试使用OneToOne单向关系从引用EmployerType执行添加新的或编辑Employer。任务很简单，但我卡住了。当我尝试添加或编辑数据时，我收到此错误：

org.springframework.http.converter.HttpMessageNotReadableException：无法读取文件：无法构建实例 tr.mis.domain.EmployerType：否字符串参数构造函数/工厂在[来源：来源：从字符串值（'1074'）反序列化的方法： java.io.PushbackInputStream@6d856887; line：1，column：609]（通过参考链：tr.mis.domain.Employer [“employerType”]）;嵌套异常是com.fasterxml.jackson.databind.JsonMappingException：可以不构造tr.mis.domain.EmployerType的实例：不从String反序列化的String-argument构造函数/工厂方法价值（'1074'）

以下是有关课程的信息。

@Entity
@Table(name = "employer")
public class Employer implements Serializable  {
    @GenericGenerator(
            name = "wikiSequenceGenerator",
            strategy = "org.hibernate.id.enhanced.SequenceStyleGenerator",
            parameters = {
                    @Parameter(name = "sequence_name", value = "WIKI_SEQUENCE"),
                    @Parameter(name = "initial_value", value = "1000"),
                    @Parameter(name = "increment_size", value = "1")
            }
    )
    @Id
    @GeneratedValue(generator = "wikiSequenceGenerator")
    private Long employerId;
    private String uid;
    private String name;
    private String address;
    private String headName;

    //@JsonIgnore
    @OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
   // @PrimaryKeyJoinColumn
    @JoinColumn(name = "employer_type_id")
    private EmployerType employerType;

    //Getters and Setters

EmployerType类

 @Entity
    @Table(name = "employertype")

    public class EmployerType {
        @GenericGenerator(
                name = "wikiSequenceGenerator",
                strategy = "org.hibernate.id.enhanced.SequenceStyleGenerator",
                parameters = {
                        @Parameter(name = "sequence_name", value = "WIKI_SEQUENCE"),
                        @Parameter(name = "initial_value", value = "1000"),
                        @Parameter(name = "increment_size", value = "1")
                }
        )
        @Id
        @GeneratedValue(generator = "wikiSequenceGenerator")

        private Long employerTypeId; 
        private String uid; 
        private String employerTypeName;

    //Getters and Setters

休息控制器

@RequestMapping(value = "/employers", method = RequestMethod.PUT)
    public Employer updateEmployer(@RequestBody Employer employer) {

        return employerRepository.save(employer);

    }

Answer 1

我通过在EmployerType类中添加String构造函数来修复此问题。

 public EmployerType(String employerTypeName) {
        // TODO Auto-generated constructor stub
    }

没有从String值反序列化的String-argument构造函数/工厂方法（'1074'）

1 个答案: