Question

嗨我想构建一个简单的xamarin.forms应用程序，所以我在这里有xaml代码所以在这段代码中我想添加网站url所以任何人都可以请帮助我需要添加xaml代码添加网站的选项网址？当我尝试使用标签和文本选项添加网址时，我想添加标签杂货下面的链接，网址仍然就像标签一样，但我希望它能以这样一种方式，如果我点击网址，它应该带我到浏览器中的网站

 <?xml version="1.0" encoding="utf-8" ?>
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
         xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
         x:Class="MyApp.AboutPage">
   <ContentPage.Content>
    <StackLayout Orientation="Vertical" HorizontalOptions="CenterAndExpand" 
 VerticalOptions="CenterAndExpand">
        <Label Text="My List" />
        <Label Text="groceries"/>
        <Button BackgroundColor="black" TextColor="White" WidthRequest="40" 
  HeightRequest="40" Text="OK" Clicked="OnRedirectMain" 
   BorderColor="Transparent" BorderWidth="1"/>

    </StackLayout>
</ContentPage.Content>
 </ContentPage>

Answer 1

<Button Text="Google" Clicked="GoGoogle" />

protected void GoGoogle(object sender, EventArgs e) {
  Device.OpenUri(new Uri("http://www.google.com"));
}

如果您不想使用按钮，则可以使用带手势的标签

<Label Text="Google">
  <Label.GestureRecognizers>
      <TapGestureRecognizer Tapped="GoGoogle" />
  </Label.GestureRecognizers>
</Label>

protected void GoGoogle(object sender, EventArgs e) {
      Device.OpenUri(new Uri("http://www.google.com"));
    }

Answer 2

<Label>

    <Label.FormattedText>
        <FormattedString>
            <Span Text="Go to SO" ForegroundColor="Blue"/>
        </FormattedString>
    </Label.FormattedText>

    <Label.GestureRecognizers>
          <TapGestureRecognizer Tapped="GoToSO" />
    </Label.GestureRecognizers>

</Label>

protected void GoToSO(object sender, EventArgs e) 
{
    Device.OpenUri(new Uri("http://www.stackoverflow.com"));
}

Answer 3

如果将ICommands与MVVM配合使用，则可以执行以下操作：

使用具有ICommand属性的ViewModel：

public class MyViewModel : INotifyPropertyChanged
{
    // details redacted ...

    public MyViewModel()
    {
        //...
        OpenGoogleCommand = new Command(() => Device.OpenUri(new Uri("http://www.google.com")));
    }
    public ICommand OpenGoogleCommand { get; }
}

然后将命令绑定在标签中：

<Label>
    <Label.FormattedText>
        <FormattedString>
            <FormattedString.Spans>
                <Span Text="Link to Google" FontSize="Large"
                      TextColor="Blue"
                      FontAttributes="Bold"/>
            </FormattedString.Spans>
        </FormattedString>
    </Label.FormattedText>
    <Label.GestureRecognizers>
        <TapGestureRecognizer Command="{Binding OpenGoogleCommand}" />
    </Label.GestureRecognizers>
</Label>

如何在xamarin.forms应用程序中添加URL

3 个答案: