Question

这是我当前的SQL查询

SELECT 
  urls.short, 
  urls.long, 
  urls.user, 
  dates.date AS date, 
  COUNT(views.short) AS views, 
  SUM(views.money) AS money 
FROM dates 
LEFT JOIN views ON dates.date = views.date
LEFT JOIN urls ON views.short = urls.short
WHERE urls.user='test'
GROUP BY dates.date, views.date
LIMIT 0, 20

它显示的结果如下：

2011-02-08 test test 1 0.003

2011-02-09 test test 6 0.016

但是当我删除

WHERE urls.user='test'

我得到了

2011-02-05 0


2011-02-06 0


2011-02-07 44kc http://google.com 27 0.031


2011-02-08 44kc http://google.com 15 0.045


2011-02-09 test test 12 0.032


2011-02-10 0

所以最后我想使用第一个查询得到第二个查询结果（显示0，当没有可用的时候）。那么解决方案是什么？

Answer 1

我不确定我是否正确理解了您的问题，但您可能需要考虑

LEFT JOIN urls ON views.short = urls.short AND urls.user='test'

sql离开加入哪里有困惑

1 个答案: