Question

我试图在运行函数run_test_args的脚本模板中编写测试用例，该函数接受三个命令：一个可选的命令行参数，一个由空格分隔的整数字符串（例如＆＃34; 1 2 3 4 5＆＃34;）用作程序提示的用户输入，以及预期输出的字符串。由于程序是使用大量数字进行测试的，因此我尝试使用seq代替以下形式的第二个参数：$(seq -s " " 100000)生成1到100,000，用空格分隔并格式化作为一个字符串。

但是，当我运行测试脚本时，该函数始终识别seq输出中的第一个元素，在上述情况下为1，作为用户输入，第二个元素作为预期输出

如何从seq获取输出并将其格式化为所有一个字符串而不是字符串数组（考虑到函数如何接收参数，似乎在做什么）？

以下是run_test_args函数和使用seq命令的测试：

run_test_args() {
(( ++total ))
echo -n "Running test $total..."
expected=$3
local ismac=0
date --version >/dev/null 2>&1
if [ $? -ne 0 ]; then
   ismac=1
fi
local start=0
if (( ismac )); then
    start=$(python -c 'import time; print time.time()')
else
    start=$(date +%s.%N)
fi
(cat << ENDOFTEXT
$2
ENDOFTEXT
) > input.txt
if timeout $MAXTIME "cat input.txt | $command $1 2>&1 | tr -d '\r' > tmp.txt"; then
    echo "failure [timed out after $MAXTIME seconds]"
else
    received=$(cat tmp.txt)
    local end=$(date +%s.%N)
    if (( ismac )); then
        end=$(python -c 'import time; print time.time()')
    else
        end=$(date +%s.%N)
    fi
    local elapsed=$(echo "scale=3; $end - $start" | bc | awk '{printf "%.3f", $0}') 
    if [ "$expected" != "$received" ]; then
        echo -e "failure\n\nExpected$line\n$expected\n"
        echo -e "Received$line\n$received\n"
    else
        echo "success [$elapsed seconds]"
        (( ++num_right ))
    fi
fi
}

run_test_args "slow" $(seq 1 100000) "Enter sequence of integers, each followed by a space: Number of inversions: 0"
run_test_args "slow" $(seq -s " " 100000 -1 1) "Enter sequence of integers, each followed by a space: Number of inversions: 4999950000"

run_test_args "" $(seq -s " " 100000) "Enter sequence of integers, each followed by a space: Number of inversions: 0"
run_test_args "" $(seq -s " " 100000 -1 1) "Enter sequence of integers, each followed by a space: Number of inversions: 4999950000"

输出seq为一个字符串[bash]

0 个答案: