Question

我对如何根据其他2个阵列正确制作数组感到困惑。

我有一个这样的数组：

let date = [1522303200000, 1522389600000, 1522476000000]

，第二个数组看起来像这样：

let people = [
  {
    "id": 0,
    "name": "Sophia Mason",
    "biography": "Lorem ...",
    "availability": [
      {
        "date": 1522303200000,
        "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
      },
      {
        "date": 1522389600000,
        "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
      },
      {
        "date": 1522476000000,
        "times": ["10:00 am", "2:30 pm", "5:00 pm"]
      },
      {
        "date": 1522735200000,
        "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
      }
    ]
  },
  {
    "id": 1,
    "name": "Brandon Hampton",
    "biography": "Lorem ...",
    "availability": [
      {
        "date": 1522303200000,
        "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
      },
      {
        "date": 1522476000000,
        "times": ["10:00 am", "2:30 pm", "5:00 pm"]
      },
      {
        "date": 1522648800000,
        "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
      },
      {
        "date": 1522735200000,
        "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
      }
    ]
  }
]

我正在尝试创建一个数组，该数组的日期为数组中每个索引的顶级，然后是每天相应的人，如果该日期有可用性。我在想类似的事情：

let calendar = [
    [
      1522303200000,
      "photographers": [
        {
          "id": 0,
          "name": "Sophia Mason",
          "biography": "Lorem ...",
          "availability": [
            {
              "date": 1522303200000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            },
            {
              "date": 1522389600000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            },
            {
              "date": 1522476000000,
              "times": ["10:00 am", "2:30 pm", "5:00 pm"]
            },
            {
              "date": 1522735200000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            }
          ]
        },
        {
          "id": 1,
          "name": "Brandon Hampton",
          "biography": "Lorem ...",
          "availability": [
            {
              "date": 1522303200000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            },
            {
              "date": 1522476000000,
              "times": ["10:00 am", "2:30 pm", "5:00 pm"]
            },
            {
              "date": 1522648800000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            },
            {
              "date": 1522735200000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            }
          ]
        }
      ]
    ],
    [
      1522303200000,
      "photographers": [
        {
          "id": 0,
          "name": "Sophia Mason",
          "biography": "Lorem ...",
          "availability": [
            {
              "date": 1522303200000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            },
            {
              "date": 1522389600000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            },
            {
              "date": 1522476000000,
              "times": ["10:00 am", "2:30 pm", "5:00 pm"]
            },
            {
              "date": 1522735200000,
              "times": ["9:00 am", "2:30 pm", "5:00 pm", "6:00 pm"]
            }
          ]
        }
      ]
    ],
    ...
  ]

但我现在仍然坚持如何解决这个问题。我可能已经看了很长时间才能真正地围绕这个。

我看了以下几个地方以获得一些想法：

stack

youtube

任何帮助将不胜感激！

Answer 1

此功能

＆＃13;

createCalendar(date, people) {
    const calendar = {};
    date.forEach(element => {
      calendar[element] = [];
      people.forEach(person => {
        if (person.availability.map(item => item.date).includes(element)) {
          calendar[element].push(person);
        }
      })
    })
    return calendar;
  }

＆＃13;

创建一个与您想到的数据结构类似的数据结构。 calendar是一个对象，其中每个键都是date，相应的值是一个数组，其中包含该日期可用性的所有people。

根据匹配值从2个数组创建（多维？）数组

1 个答案: