我有这段代码:
$url = 'http://example.com/523223.json?';
$json= file_get_contents($url);
$data = json_decode($json);
$rows = $data->{'items'};
foreach ($rows as $row) {
echo '<p>';
$title = $row->name;
$description = $row->description;
$link = $row->link;
$image_link = $row->thumbnails;
$path = $image_link->large;
$filename = basename($path);
try {
Image::make($path)->save(public_path('storage/posts/' . $filename));
} catch (\Intervention\Image\Exception\NotReadableException $e) {
Image::make($path)->save(public_path('storage/posts/' . 'https://lh3.googleusercontent.com/yI8LPDBhjvqLR1mQMitJlibZdWqaYAlMVUJK6zpBQkOb_Bk03qn_l2SQyn5yY__KZcY-=w300-rw'));
}
$post = new Post;
$post->title = $title;
$post->body = '..';
$post->excerpt = $description;
$post->meta_description = $link;
$post->image = 'posts/' . $filename;
$post->save();
}
它的作用是从JSON URL获取内容并将其存储到基于LaraveL的数据库中。所以问题是它存储的数据从最新到最旧,但我想要的是存储从最旧到最新的项目。 这是第一个问题,第二个问题是如何使它只存储最新的那些不重复已经存储的那些并仅检查那些只是新的?
答案 0 :(得分:0)
以下是使用array_reverse完成的方法:
$url = 'http://example.com/523223.json?';
$json= file_get_contents($url);
$data = json_decode($json);
$rows = $data->{'items'};
foreach (array_reverse($rows) as $row) {
echo '<p>';
$title = $row->name;
$description = $row->description;
$link = $row->link;
$image_link = $row->thumbnail;
$path = $image_link;
$filename = basename($path);
try {
Image::make($path)->save(public_path('storage/posts/' . $filename));
} catch (\Intervention\Image\Exception\NotReadableException $e) {
Image::make($path)->save(public_path('storage/posts/' . 'https://lh3.googleusercontent.com/yI8LPDBhjvqLR1mQMitJlibZdWqaYAlMVUJK6zpBQkOb_Bk03qn_l2SQyn5yY__KZcY-=w300-rw'));
}
$post = new Post;
$post->title = $title;
$post->body = '..';
$post->excerpt = $description;
$post->meta_description = $link;
$post->slug = $link;
$post->image = 'posts/' . $filename;
$post->save();
}