Question

我有以下用例，我有两个数组，如下面的

arr1=[{room_no:1,bed_no:'1A'},
      {room_no:1,bed_no:'1B'},
      {room_no:2,bed_no:'2A'},
      {room_no:3,bed_no:'3A'},
      {room_no:3,bed_no:'3B'},
      {room_no:4,bed_no:'4A'}]

 arr2=[
       { patient_details:[{name:'patient1',age:22}],
         patient_room_details:[{room_no:1,bed_no:'1A'}],
         status:'occupied'
       },
       { patient_room_details:[{room_no:1,bed_no:'1B'},
         status:'available'
       },
       {  patient_details:[{name:'patient2',age:32}],
          patient_room_details:[{room_no:2,bed_no:'2A'}],
          status:'occupied'
       }
       { patient_room_details:[{room_no:3,bed_no:'3A'},
         status:'cleaning'
       },
      ]

我试图比较第一个数组中的room_no和bed_no与第二个数组patient_room_details。如果找到匹配，则将匹配的对象推送到具有patient_details，patient_room_details和status的结果数组。如果找不到匹配项，我需要将状态仅推送为AVAILABLE。

我无法将状态推送为AVAILABLE，如果找不到匹配项，任何帮助都将不胜感激

，最终结果就像

result=[
       { patient_details:[{name:'patient1',age:22}],
         patient_room_details:[{room_no:1,bed_no:'1A'}],
         status:'occupied'
       },
       { patient_room_details:[{room_no:1,bed_no:'1B'},
         status:'available'
       },
       {  patient_details:[{name:'patient2',age:32}],
          patient_room_details:[{room_no:2,bed_no:'2A'}],
          status:'occupied'
       },
       { patient_room_details:[{room_no:3,bed_no:'3A'},
         status:'cleaning'
       },
       { patient_room_details:[{room_no:3,bed_no:'3B'},
         status:'available'
       },
       { patient_room_details:[{room_no:4,bed_no:'4A'},
         status:'available'
       },
      ]

Answer 1

Array.prototype.map()和Map可以结合使用arrays有效地比较keys。

请参阅下面的实例。

// Input.
const rooms = [{room_no: 1, bed_no: '1A'}, {room_no: 1, bed_no: '1B'}, {room_no: 2, bed_no: '2A'}, {room_no: 3, bed_no: '3A'}, {room_no: 3, bed_no: '3B'}, {room_no: 4,bed_no: '4A'}]
const patients = [{patient: {name: 'patient1', age: 22}, room: {room_no: 1,bed_no: '1A'}, status: 'occupied'}, {room: {room_no: 1, bed_no: '1B'}, status: 'available'}, {patient: {name:'patient2',age:32}, room: {room_no:2,bed_no: '2A'}, status:'occupied' }, {room: {room_no: 3, bed_no:'3A'}, status: 'cleaning'}]

// Room Status.
const roomStatus = (rooms, patients) => (m => rooms.map(r => m.get(`${r.room_no} ${r.bed_no}`) || {room: r, status: 'available'}))(new Map(patients.map(x => [`${x.room.room_no} ${x.room.bed_no}`, x])))

// Output.
const output = roomStatus(rooms, patients)

// Proof.
console.log(output)

比较数组并将数据推送到索引位置

1 个答案: