Question

下面是文本，我想在Sql中仅返回双引号中的数据。

输入 -

Task "Testing Data" started successfully.

输出：

Testing Data

Answer 1

尝试以下。

DECLARE @testData VARCHAR(100) = 'Task : "Testing Data" started successfully.' 

SELECT Substring(@testData, Charindex('"', @testData, 1) + 1, 
              Len(@testData) - Charindex('"', @testData) - 
              Charindex('"', Reverse(@testData))) AS [Output];

<强>输出

+--------------+
| Output       |
+--------------+
| Testing Data |
+--------------+

Answer 2

<强> MYsql的

SELECT replace(SUBSTRING_INDEX
('"Testing Data" started successfully.', '"', 2),'"','')

<强> SQLServer的

select replace(substring(@string,1,charindex('"',@string,2)),'"','')

Answer 3

请使用：

DECLARE @Text varchar(100) = 'Task : "Testing Data" started successfully.'
SELECT SUBSTRING(@Text,CHARINDEX('"',@Text)+1, CHARINDEX('"',@Text,CHARINDEX('"',@Text)+1)-CHARINDEX('"',@Text)-1)

Answer 4

在mySQL中试试这个：

set @myVar = 'Task : "Testing Data" started successfully';
select substring_index(substring_index(@myVar, '"', -2),'"',1)

Answer 5

MS SQL SERVER -

我使用substring，charindex，patindex和iif函数来解决此问题。请在下面找到我的查询 -

declare @tmp_tbl table (id int identity, Some_string nvarchar(1000))

insert into @tmp_tbl (Some_string)
select '"Testing Data" example' union all
select 'Test data "Testing Data"' union all
select 'Test "Testing Data" example' union all
select 'Test example' union all
select 'Test " example' union all
select 'Test "" example' union all
select 'Test "Testing Data" example "Testing 123 '

select
    id,
    iif(
        patindex('%"%"%', Some_string) = 0,
        NULL,
        substring(
            Some_string,
            (charindex('"', Some_string) + 1),
            charindex('"', Some_string, charindex('"', Some_string) + 1) - charindex('"', Some_string) - 1
        )
    )
from
    @tmp_tbl

在Sql中双引号之间提取数据

5 个答案: