使用总和

Question

[ 

{t_id :"1",  val1 : "1" ,   title:"cash to purchase",   unit :"bag"},

{t_id :"1"  ,val1 : "1" ,  title:"cash to purchase", unit :"bag"}

{t_id :"1",val1 : "1" , title:"cash to purchase", unit :"bag"}

{t_id :"2",val1 : "4" , title:"offload", unit :"bag"},

{t_id :"2",val1 : "5" , title:"onroad", unit :"bag"},

{t_id :"3", val1 : "5" , title:"Onroad", unit :"bag"},

{t_id :"3", val1 : "6" , title:"Onroad", unit :"bag"},

]

我希望按t_id进行分组，并根据每个t_id找到val1的总和，并将val1除以t_id的总数....例如：数组中有三个t-id 1，总和为三个t_id是3（val1）..所以val1必须是3 /总t_id（即3/3）......

然后我想要我的HTML

标题：购买现金

包：1（即（3/3）

名称：卸载

包：4.5（即9/2）

标题：普通道路

包：5.5（即11/2）......总共2是t_id

Answer 1

这样做：

var array = [{t_id:"1",val1:"1",title:"cash to purchase",unit:"bag"},{t_id:"1",val1:"1",title:"cash to purchase",unit:"bag"},{t_id:"1",val1:"1",title:"cash to purchase",unit:"bag"},{t_id:"2",val1:"4",title:"offload",unit:"bag"},{t_id:"2",val1:"5",title:"onroad",unit:"bag"},{t_id:"3",val1:"5",title:"Onroad",unit:"bag"},{t_id:"3",val1:"6",title:"Onroad",unit:"bag"}];


var grouped = [];

array.forEach(function(o) {
  var count = 0;
  if (!this[o.t_id]) {
    this[o.t_id] = {
      t_id: o.t_id,
      val1: 0,
      title: o.title,
      counter: count
    };
    grouped.push(this[o.t_id]);
  }
  this[o.t_id].val1 += Number(o.val1);
  this[o.t_id].counter += Number(++count);
}, Object.create(null));

console.log(grouped);

现在在HTML中显示如下：Bag: {{result.val1/result.counter}}

Answer 2

我不知道下面的脚本是否适合你，但输出就像你想要的那样。

＆＃13;

＆＃13;

var sources = [
{t_id: "1", val1: "1", title: "cash to purchase", unit: "bag"},
{t_id: "1", val1: "1", title: "cash to purchase", unit: "bag"},
{t_id: "1", val1: "1", title: "cash to purchase", unit: "bag"},
{t_id: "2", val1: "4", title:"offload", unit :"bag"},
{t_id: "2", val1: "5", title:"onroad", unit :"bag"},
{t_id: "3", val1: "5", title:"Onroad", unit :"bag"},
{t_id: "3", val1: "6", title:"Onroad", unit :"bag"}
];

var groups = {};
for(var i in sources){
	var source = sources[i];
	if(typeof groups[source.t_id] !== 'undefined'){
    	groups[source.t_id].sum_of_val1 += Number(source.val1);
    	groups[source.t_id].num_of_items += 1;
    }else{
    	groups[source.t_id] = source;
        groups[source.t_id].sum_of_val1 = Number(source.val1);
    	groups[source.t_id].num_of_items = 1;
    }
}

// print out put
for(var i in groups){
	var group = groups[i];
	
    document.write("Title: " + group.title + "<br/>Bag: " + (group.sum_of_val1 / group.num_of_items) + " (ie.: " + group.sum_of_val1 + " / " + group.num_of_items+ ")<br/><br/>");
}

＆＃13;

＆＃13;

＆＃13;