我想从firefox扩展程序向Web服务器发送POST请求。
我发现这个例子发送POST请求; https://developer.mozilla.org/en/Creating_Sandboxed_HTTP_Connections#HTTP_notifications
但我无法让它发挥作用。
我目前有这样的代码;
var ioService = Components.classes["@mozilla.org/network/io-service;1"]
.getService(Components.interfaces.nsIIOService);
var uri = ioService.newURI("http://www.google.com", null, null);
gChannel = ioService.newChannelFromURI(uri);
postData = "a=1&b=2&c=3";
var inputStream = Components.classes["@mozilla.org/io/string-input-stream;1"]
.createInstance(Components.interfaces.nsIStringInputStream);
inputStream.setData(postData, postData.length);
var uploadChannel = gChannel.QueryInterface(Components.interfaces.nsIUploadChannel);
uploadChannel.setUploadStream(inputStream, "application/x-www-form-urlencoded", -1);
uploadChannel.requestMethod = "POST";
uploadChannel.open();
但我收到有关“无法修改WrappedNative属性”的错误
答案 0 :(得分:4)
如何使用XMLHttpRequest对象。 扩展开发中没有相同的原始策略
答案 1 :(得分:3)
我使用以下代码来测试是否存在URL:
if( typeof XMLHttpRequest == "undefined" ){
var req = Components.classes["@mozilla.org/xmlextras/xmlhttprequest;1"]
.createInstance();
}
else{
var req = new XMLHttpRequest();
}
try{
req.open( "GET", "https://" + request.URI.host + request.URI.path );
var timeOutID = httpNowhere._getWindow().setTimeout(function () {
req.abort();
Services.prompt.alert(null,"Info","nok "+ "https://" + request.URI.host
+ request.URI.path );
}, (redirectTimer));
req.onreadystatechange = function (e) {
if (req.readyState==4){
Services.prompt.alert(null,"Info","ok "+ "https://" + request.URI.host
+ request.URI.path );
req.abort();
}
}
req.send( null );
} catch (err) {
Services.prompt.alert(null,"Info",err);
}
答案 2 :(得分:1)
requestMethod是nsIHttpChannel上的一个属性,因此您需要先在gChannel上调用QueryInterface,然后才能进行设置。