Question

我需要帮助来总结某些条件下的数组值

我有这个结果查询：

我想计算每个用户的调用总和，我尝试这样，但它显示所有查询的总和[用户]

$array_out_ = array();
$usercalls =  $usertalk =  $userpause =  $userwait = $userdispo = $userdead = 0;
    foreach ($queryusers2 as $user) {
            $current_user = $user['user'];
            $usercalls += $user['calls'];
            $usertalk += $user['talk'];
            $userpause += $user['pause'];
            $userwait += $user['wait'];
            $userdispo += $user['dispo'];
            $userdead += $user['dead'];

        $array_out_[$current_user]['calls'] = $usercalls;
        $array_out_[$current_user]['talk'] = $usertalk;
        $array_out_[$current_user]['pause'] = $userpause;
        $array_out_[$current_user]['wait'] = $userwait;
        $array_out_[$current_user]['dispo'] = $userdispo;
        $array_out_[$current_user]['dead'] = $userdead;
    }

此方法返回$ usercalls（代理29的305）和（代理117的436）但是我想要305代理商29和代理商117只有131

由于

Answer 1

我建议您将查询SQL更改为类似的内容，您可以在其中对数据进行分组和汇总。

SELECT
   tn.user,
   SUM(tn.calls) AS usercalls,
   SUM(tn.talk) AS usertalk,
   SUM(tn.pause) AS userpause,
   SUM(tn.wait) AS userwait,
   SUM(tn.dispo) AS userdispo,
   SUM(tn.dead) AS userdead
FROM tablename tn
GROUP BY tn.user

这将返回你需要的东西：

agent29,  305, ...

agent117, 436, ...

Answer 2

您的值$usercalls，$usertalk，...未重新初始化。并为所有用户累积。您的代码仅适用于第一个用户，仅因为您的列表是由用户订购的。

你可以初始化一个数组并直接在其中求和：

$array_out_ = array();

foreach ($queryusers2 as $user)
{
    $current_user = $user['user'];

    if (!isset($array_out_[$current_user])) {
        $array_out_[$current_user] = [
            'calls' => 0, 'talk' => 0, 'pause' => 0, 'wait' => 0,
            'dispo' => 0, 'dead' => 0
        ];
    }

    $array_out_[$current_user]['calls'] += $user['calls'];
    $array_out_[$current_user]['talk'] += $user['talk'];
    $array_out_[$current_user]['pause'] += $user['pause'];
    $array_out_[$current_user]['wait'] += $user['wait'];
    $array_out_[$current_user]['dispo'] += $user['dispo'];
    $array_out_[$current_user]['dead'] += $user['dead'];
}

另见the answer of Enric Borrallo Rodriguez

PHP - 按定义的值

2 个答案: