Question

我试图执行以下sql查询

function getLargest(array) {
    return array
        .map(String)
        .sort((a, b) => (b + a) - (a + b))
        .join('');
}

console.log(getLargest([1, 3, 34, 44, 4, 45, 6, 76, 9, 98, 23]));
console.log([1, 3, 34, 44, 4, 45, 6, 76, 9, 98, 23].sort().reverse().join(''));

由于WHERE条件不起作用，我无法执行此操作，它为我提供了整个表中最大数字的值。

我做错了什么？

Answer 1

您的查询是否正确

SELECT MAX(amount) AS LargestPrice FROM au_bids WHERE product = 73

查看现场演示

http://sqlfiddle.com/#!9/11bbf1/2

Answer 2

您的查询是错误的

mysql> select * from Customers;
+-------------+---------------+
| customer_id | customer_name |
+-------------+---------------+
|           1 | Arun          |
|           2 | kumar         |
|           4 | bbbbb         |
|           5 | mmmmm         |
|           6 | kkkk          |
|           3 | eeeeee        |
+-------------+---------------+
6 rows in set (0.00 sec)

mysql> select max(customer_id) from Customers where customer_id=2;
+------------------+
| max(customer_id) |
+------------------+
|                2 |
+------------------+
1 row in set (0.00 sec)

SELECT MAX与WHERE条件

2 个答案: