Question

好的，我是jQuery JSON的新手。我正在尝试访问以下json输出中的actions > name节点。看起来“actions”是“data”数组中的一个数组。我获得json结果的方式我可以使用fb.message正确访问“消息”部分，我可以使用fb.from.name访问“from”下的“name”节点。那么我将如何访问“actions” array 下的“name”节点？

感谢您的帮助!!

CODE：

({ "data": [{
         "id": "1755670903_1287007912714",
         "from": {
            "name": "LifeBridge Church",
            "id": "1755670903"
         },
         "message": "Due to weather, church service tomorrow is canceled. See you next week!",
         "icon": "http://photos-d.ak.fbcdn.net/photos-ak-snc1/v27562/23/2231777543/app_2_2231777543_9553.gif",
         "actions": [
            {
               "name": "\u0040lifebridgeTX on Twitter",
               "link": "http://twitter.com/lifebridgeTX?utm_source=fb&utm_medium=fb&utm_campaign=lifebridgeTX&utm_content=33711605665505280"
            }
         ],
         "type": "status",
         "application": {
            "name": "Twitter",
            "id": "2231777543"
         },
         "created_time": "2011-02-05T02:20:48+0000",
         "updated_time": "2011-02-05T02:20:48+0000"
      },
      {
         "id": "1755670903_1281724020620",
         "from": {
            "name": "LifeBridge Church",
            "id": "1755670903"
         },
         "message": "Service tonight at 5:30... meet us at Eddins Elementary school in McKinney.  http://see.sc/8l4Cwo || Praying that God is greatly glorified!",
         "icon": "http://photos-d.ak.fbcdn.net/photos-ak-snc1/v27562/23/2231777543/app_2_2231777543_9553.gif",
         "actions": [
            {
               "name": "\u0040lifebridgeTX on Twitter",
               "link": "http://twitter.com/lifebridgeTX?utm_source=fb&utm_medium=fb&utm_campaign=lifebridgeTX&utm_content=31388610301272065"
            }
         ],
         "type": "status",
         "application": {
            "name": "Twitter",
            "id": "2231777543"
         },
         "created_time": "2011-01-29T16:30:03+0000",
         "updated_time": "2011-01-29T16:30:03+0000"
      }]
});

其他问题的后续代码：

$.each(json.data,function(i,fb){
    if (!fb.message) continue;
    facebookPost += '<li class="ui-li ui-li-static ui-btn-up-c" role="option" data-theme="c">' + fb.message + ' <br /><span class="via">' + fb.created_at + ' via ' + fb.actions[0].name + '</span></li>';
    $('#facebookPosts li:first').after(facebookPost);
});

Answer 1

JSON对象只是普通的javascript对象，以通常的方式访问它们，以获得i数据项的j动作，您可以使用以下代码。要获得每个中的第一个，您只需硬编码i=j=0。

jsonResponse.data[i].actions[j].name

Answer 2

我假设当你说fb时fb = data[0]。然后：

fb.actions; // Gives actions ARRAY
fb.actions[0]; // Gives first OBJECT in actions ARRAY
fb.actions[0].name; // Gives the name VALUE of the first OBJECT in actions ARRAY

根据评论中的问题，在值不存在时跳过项目：

$.each(json.data,function(i,fb){
    if (!fb.message) return true; // true to keep going, false to quit immediately
    facebookPost += '<li class="ui-li ui-li-static ui-btn-up-c" role="option" data-theme="c">' + fb.message + ' <br /><span class="via">' + fb.created_at + ' via ' + fb.actions[0].name + '</span></li>';
    $('#facebookPosts li:first').after(facebookPost);
});

Answer 3

您可以访问数组中的第一个元素：

fb.actions[0].name

$ .getJSON的问题 - 看起来像数组中的数组

3 个答案: