Question

这是我的代码，当我尝试运行它并选择时头痛，出汗，虚弱，寒战，骨痛和关节疼痛病毒感染。课程活动开始而不是chickengunia.class。这有什么问题？

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.questionnaire);


    final Button go = (Button) findViewById(R.id.submit);

    go.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            if (headache.isChecked() && sweating.isChecked() && weakness.isChecked() && chills.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, ViralFever.class);
                startActivity(Intents);

            }

  else   if (headache.isChecked() && bonepain.isChecked() && weakness.isChecked() && rashes.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, Dengue.class);`enter code here`
                startActivity(Intents);

            }

else    if (headache.isChecked() && sweating.isChecked() && skinyellow.isChecked() && palestools.isChecked() && abdoman.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, Jaundice.class);
                startActivity(Intents);

            }
    else     if (diarrhea.isChecked() && sweating.isChecked() && nausea.isChecked() && dehydration.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, Cholera.class);
                startActivity(Intents);

            }
            else if (headache.isChecked() && sweating.isChecked() && weakness.isChecked() && shiver.isChecked()&& abdoman.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, Malaria.class);
                startActivity(Intents);

            }
     else    if (headache.isChecked() && sweating.isChecked() && weakness.isChecked() && chills.isChecked()  && bonepain.isChecked() && jointpain.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, Chickengunia.class);
                startActivity(Intents);

            }
       else   if (headache.isChecked() && sweating.isChecked() && weakness.isChecked() && chills.isChecked()&& diarrhea.isChecked()&& nausea.isChecked()&& sorethroat.isChecked()&& cough.isChecked()&& runningnose.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, Swineflu.class);
                startActivity(Intents);

            }
      else   if (headache.isChecked() && sweating.isChecked() && weakness.isChecked() && chills.isChecked()&& rashes.isChecked()) {
                Intent Intents = new Intent(Questionnaire.this, Typhoid.class);
                startActivity(Intents);

            }
            else
            {
                Intent Intents = new Intent(Questionnaire.this, Checkup.class);
                startActivity(Intents);
            }
            }

    });

}

}

这是我的类文件，它只执行第一个if语句，因为我选择的按钮位于该语句中。

Answer 1

<强>原因：问题似乎是您ViralFever语句之前的Chickengunia检查。会发生什么情况，它首先检查ViralFever的症状，其症状与Chickengunia的症状子集相同。

<强>解决方案：您可以做的是交换ViralFever和Chickengunia的代码。

if (headache.isChecked() && sweating.isChecked() && weakness.isChecked() && chills.isChecked()  && bonepain.isChecked() && jointpain.isChecked()) {
            Intent Intents = new Intent(Questionnaire.this, Chickengunia.class);
            startActivity(Intents);

        }

  else     if (headache.isChecked() && sweating.isChecked() && weakness.isChecked() && chills.isChecked()) {
            Intent Intents = new Intent(Questionnaire.this, ViralFever.class);
            startActivity(Intents);

        }

依旧......

Answer 2

 if(isHeadeck&& isPain&&isSweat&&isChills){
        if(jointPin&&isBonepain)
            Intent Intents = new Intent(Questionnaire.this, Chickengunia.class);
             startActivity(Intents);
        else
        Intent Intents = new Intent(Questionnaire.this, ViralFever.class);
        startActivity(Intents);
    }

如何区分android中的单选按钮？

2 个答案: