程序中的分割错误，通过结构和结构函数来比较两个有理数

Question

#include<stdio.h>
#include<stdbool.h>

struct  rational{  
  int numerator;
  int denominator;
};


bool equal(struct rational *rational_number1,struct rational *rational_number2);

 void reduce(struct rational *inputrational,struct rational *outputrational);


int main()

{

int p,q,r,s;


printf("details of number 1\n");

printf("numerator\n");

scanf("%d",&q);

printf("denominator\n");

scanf("%d",&p);

printf("details of number 2\n");


printf("numerator\n");

scanf("%d",&s);

printf("denominator\n");

scanf("%d",&r);

struct rational *rationalnumber1,*rationalnumber2;

rationalnumber1->denominator=p;

rationalnumber1->numerator=q;

rationalnumber2->denominator=r;

rationalnumber2->numerator=s;


if(equal(rationalnumber1,rationalnumber2))

printf("both are equal");

else 

printf("both are unequal");

}

bool equal(struct rational *rational_number1,struct rational *rational_number2)


{

struct rational *inputrational1,*inputrational2;

inputrational1=rational_number1;

inputrational2=rational_number2;

struct rational *outputrational1;

struct rational *outputrational2;

outputrational1->numerator=0;

outputrational1->denominator=0;

outputrational2->numerator=0;
outputrational2->denominator=0;

reduce(inputrational1,outputrational1);
reduce(inputrational2,outputrational2);
if(outputrational1==outputrational2)
return true;

}


void reduce(struct rational *inputrational,struct rational *outputrational)


{


int i,f;

for(i=1;(i<=inputrational->numerator)&&(i<=inputrational->denominator);i++)
{

    if((inputrational->numerator%i==0)&&(inputrational->denominator%i==0))
{

    f=i;
}


outputrational->numerator=(inputrational->numerator)/f;

outputrational->denominator=(inputrational->denominator)/f;


}

}

Answer 1

您已声明指向结构的指针，但您尚未为它们分配内存。 struct rational *rationalnumber1,*rationalnumber2; rationalnumber1->denominator=p;

您必须按如下方式分配内存： struct rational *rationalnumber1 = malloc(sizeof(*rationalnumber1));  在你写下面的陈述之前： rationalnumber1->denominator=p; 你必须为rationalnumber2做这件事。

虽然我们在这里，但你并不需要声明指针。 您可以向结构声明对象。 您可以将定义的对象的地址传递给您定义的函数。