Question

我试图弄清楚为什么我的ApiException仍然返回一个text / html响应而不是一个json响应，如ApiException render方法所示。它给了我正确的错误信息，但它没有将它呈现为json。

/**
 * Get the checklist (depending on type - send from Vue model)
 */
public function fetchChecklist(Request $request)
{
    $id = $request->input('projectId');
    $type = $request->input('type');

    if (empty($id)) {
        throw new ApiException('Project was not provided.');
    }

    if (! $project = RoofingProject::find($id)) {
        throw new ApiException('Project not found.');
    }

    if (empty($type)) {
        throw new ApiException('No checklist type was provided.');
    }

    switch ($request->input('type')) {
        case 'permitting':
            $items = $project->permittingChecklist;
            break;

        case 'permit':
            $items = $project->permitReqChecklist;
            break;

        default:
            throw new ApiException('Checklist not found.');
            break;
    }

    return [
        'status' => 'success',
        'message' => '',
        'items' => $items
    ];
}

应用\例外\ ApiException.php

<?php

namespace App\Exceptions;

class ApiException extends \Exception
{
    public function render($request)
    {
        return response()->json(['status' => 'error', 'error' => $this->message]);
    }
}

Answer 1

在您对API的请求中，您可以尝试将以下内容添加到head / curl调用中以指定数据类型：

"Accept: application/json"

laravel应用程序正在查找请求是否需要json。

Answer 2

将以下标头设置为这样对我来说很有用

"x-requested-with": "XMLHttpRequest"

Laravel ApiException返回HTML响应而不是JSON

2 个答案: