Question

如果我拥有属于大集合的以下文档的ID以及 newBusinessId 来更新这些文档。像这样：

const newBusinessId = '8abc4cef176aa342154d00c0'
const paymentsIds = ['5aba5cef176aa342154d2345', '5aba5cef176aa342154d6789']

这些ID属于我的数据库中的以下文档：

[
  {
    _id: '5aba5cef176aa342154d2345',
    state: 'MATURE',
    comment: 'some comment 1',
    startComment: 'some different comment 1',
    expense: 2,
    startExpense: 2,
    businessId: '5aba5cef176aa342154d9876'
  },
  {
    _id: '5aba5cef176aa342154d6789',
    state: 'MATURE',
    comment: 'some comment 2',
    startComment: 'some comment 2',
    expense: 3,
    startExpense: 1,
    businessId: '5aba5cef176aa342154d5432'
  },
]

我想使用相同的 businessId ： newBusinessId 更新这些文档，状态值为 INIT 以及使用（ startComment，startExpense ）的值设置的字段（评论，费用），以便更新后可以得到以下结果：

[
  {
    _id: '5aba5cef176aa342154d2345',
    state: 'INIT',
    comment: 'some different comment 1',
    startComment: 'some different comment 1',
    expense: 2,
    startExpense: 2,
    businessId: '8abc4cef176aa342154d00c0'
  },
  {
    _id: '5aba5cef176aa342154d6789',
    state: 'INIT',
    comment: 'some comment 2',
    startComment: 'some comment 2',
    expense: 1,
    startExpense: 1,
    businessId: '8abc4cef176aa342154d00c0'
  },
]

任何想法如何？我很感激你的努力！

Answer 1

为了在同一个对象中更新具有另一个字段值的字段（例如，expense = startExpense），你必须迭代，试试这个：

yourModel.find().forEach(
    function (elem) {
        yourModel.update(
            {
                _id: { $in: paymentsIds }
            },
            {
                $set: {
                    state : 'INIT',
                    comment : elem.startComment,
                    expense : elem.startExpense,
                    BusinessId : newBusinessId
                }
            }
        );
    }
);

如何使用mongodb

1 个答案: