Question

我们如何根据另一个对象数组值对对象数组进行排序，就像我们有一个对象数组一样：

var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}]

在这个索引1,2,3,4,5具有相同的键“tEnd”的值，即3和1所以我只需要根据另一个对象数组排序那些索引

var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}]

此处，用户ID 597,605,617,553,616的分数值为85,95,85,100,95

所以根据得分，我想排序我的第一个数组输出应该是：

[{"userID":554,"tEnd":6},{"userID":605,"tEnd":3},{"userID":597,"tEnd":3},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":617,"tEnd":1},{"userID":596,"tEnd":0}]

Answer 1

您可以获取tEnd的增量并找到score并获取该增量。

＆＃13;

function getScore(uID) {
    return (_profsort.find(({ userID }) => userID === uID) || { score: 0 }).score;
}

var _userEnd = [{ userID: 554, tEnd: 6 }, { userID: 597, tEnd: 3 }, { userID: 605, tEnd: 3 }, { userID: 617, tEnd: 1 }, { userID: 553, tEnd: 1 }, { userID: 616, tEnd: 1 }, { userID: 596, tEnd: 0 }],
    _profsort = [{ userID: 596, score: 100 }, { userID: 616, score: 95 }, { userID: 553, score: 100 }, { userID: 617, score: 85 }, { userID: 605, score: 95 }, { userID: 597, score: 85 }, { userID: 554, score: 100 }];
    
_userEnd.sort(function (a, b) {
    return b.tEnd - a.tEnd || getScore(b.userID) - getScore(a.userID);
});

console.log(_userEnd);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 2

使用sort和find

var fnGetScore = uid => _profsort.find(s => s.userID == uid).score; //method to get the score value based on userId

var output = _userEnd.sort( (a, b) => 
        (b.tEnd - a.tEnd) || 
           fnGetScore(b.userID) - fnGetScore(b.userID)) //compare tEnd first and if they are same, compare the score value

<强>演示

＆＃13;

var _userEnd = [{
  "userID": 554,
  "tEnd": 6
}, {
  "userID": 597,
  "tEnd": 3
}, {
  "userID": 605,
  "tEnd": 3
}, {
  "userID": 617,
  "tEnd": 1
}, {
  "userID": 553,
  "tEnd": 1
}, {
  "userID": 616,
  "tEnd": 1
}, {
  "userID": 596,
  "tEnd": 0
}];

var _profsort = [{
  "userID": 596,
  "score": 100
}, {
  "userID": 616,
  "score": 95
}, {
  "userID": 553,
  "score": 100
}, {
  "userID": 617,
  "score": 85
}, {
  "userID": 605,
  "score": 95
}, {
  "userID": 597,
  "score": 85
}, {
  "userID": 554,
  "score": 100
}];

var fnGetScore = uid => _profsort.find(s => s.userID == uid).score;

var output = _userEnd.sort((a, b) => (b.tEnd - a.tEnd) || fnGetScore(b.userID) - fnGetScore(b.userID))

console.log(output);

＆＃13;

Answer 3

使用score按userID创建Array.reduce的对象。按tEnd排序，如果score按sortObject userId排序，则按var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}] var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}] var sortObj = _profsort.reduce((r, o) => { r[o.userID] = o.score; return r; }, Object.create(null)); _userEnd.sort((a, b) => b.tEnd - a.tEnd || sortObj[b.userID] - sortObj[a.userID]); console.log(_userEnd);排序：

{{1}}

我们如何根据节点js中的另一个对象数组值对对象数组进行排序

3 个答案: