我正在努力使用LINQ来 SQL XML。我正在关注示例并取得一些好成绩。但是我遇到了一个问题,希望有人可以帮助我。
<root>
<MyItem Host="00155DFF045C" LastName="HOUSTON" FirstName="WHITNEY" >
<TimeStamp ComputerTime="02/07/2011 - 21:41:53.715">
<Group Name="Group1">
<Variable ID="1001" Value="Happy" >
</Variable>
</Group>
<Group Name="Group2">
<Variable ID="2000" Value="Monday" >
</Variable>
<Variable ID="2001" Value="Tuesday" >
</Variable>
</Group>
<Group Name="Group3">
<Variable ID="3000" Value="January" >
</Variable>
<Variable ID="3001" Value="February" >
</Variable>
</Group>
<Group Name="Groupe4">
<Variable ID="4001" Value="108.000000" >
</Variable>
<Variable ID="4002" Value="800" >
</Variable>
</Group>
<Group Name="CustomGroup">
<Variable ID="1001000" Value="1.000000" >
</Variable>
</Group>
</TimeStamp>
</MyItem>
<MyItem>
...
...
</MyItem>
</root>
由于教程,我正确地获得了{Host="00155DFF045C" LastName="HOUSTON" FirstName="WHITNEY}
之类的信息。
但我需要获得更多信息。如何使用属于Value
的{{1}}检索ID="4001"
变量元素?
我目前的代码是:
Groupe4
使用此代码,我可以正确获取XElement xmlTweets = XElement.Parse(e.Result);
var toto = from tweet in xmlTweets.Descendants("MyItem").Take(10)
orderby tweet.Element("TimeStamp").Attribute("ComputerTime").Value descending
select new History {
DisplayName = tweet.Attribute("PatientFirstName").Value + " " +
tweet.Attribute("PatientLastName").Value
};
的值。我想得到变量DisplayName
的值,即值4001
。
答案 0 :(得分:2)
如果您对特定元素有引用,则可以使用Element()
或Attribute()
方法从其任何嵌套元素中获取值。您可以使用Elements()
或Attributes()
获取这些列表,以对它们执行LINQ查询。假设我们有对root元素的引用,您可以获得以下信息:
XElement root = ...;
XElement myItem = root.Element("MyItem"); // get the first "MyItem" element
string Host = myItem.Attribute("Host").Value; // get value of "Host" attribute
string LastName = myItem.Attribute("LastName").Value; // get value of "LastName" attribute
string FirstName = myItem.Attribute("FirstName").Value; // get value of "FirstName" attribute
// find "Groupe4"
XElement Groupe4 = (from g in myItem.Element("TimeStamp")
.Elements("Group")
where g.Attribute("Name").Value == "Groupe4"
select g) // only one element should be found
.Single(); // assign that element to variable Groupe4
// Get Value of Variable with ID = 4001
double Value4001 = (from v in Groupe4.Elements("Variable") // of all Variable elements
where (int)v.Attribute("ID") == 4001 // choose elements where ID = 4001
select (double)v.Attribute("Value")) // select the Value
.Single(); // assign that value to variable Value 4001
因此,要将其应用于您的查询,您可以执行以下操作:
XElement xmlTweets = XElement.Parse(e.Result);
var id = 4001; // the ID to find
var toto = from tweet in xmlTweets.Descendants("MyItem")
.Take(10)
orderby (DateTime)tweet.Element("TimeStamp")
.Attribute("ComputerTime") descending
select new History {
DisplayName = String.Format("{0} {1}",
tweet.Attribute("PatientFirstName").Value,
tweet.Attribute("PatientLastName").Value),
// find the Variable with matching ID and get its Value as a double
Value = (from v in tweet.Descendants("Variable")
where (int)v.Attribute("ID") == id
select (double)v.Attribute("Value"))
.Single()
};
答案 1 :(得分:1)
一旦有XElement
变量名为myItemElement
,
myItemElement
.Element("TimeStamp")
.Elements("Group")
.FirstOrDefault(x => x.Attribute("Name") != null && x.Attribute("Name").Value == "Groupe4")
.Elements("Variable")
.FirstOrDefault(x => x.Attribute("ID") != null && x.Attribute("ID").Value == "4001")
.Attribute("Value").Value;