Question

所以我有4个名为$description,$hscode,$from,$to的php变量我希望通过AJAX请求发送这些变量。我的不完整尝试是这样的：

function searchFilter(page_num) {
  page_num = page_num?page_num:0;

    $.ajax({
        type: 'POST',
        url: 'getData.php',
       data: { page : +page_num, "desc" : "<?php  print $description ?>","hscode" : "<?php  print $hscode ?>","from" : "<?php  print $from ?>","to" : "<?php $to ?>" },

        beforeSend: function () {
            $('.container-fluid').waitMe({
                   effect : 'stretch',
                   bg : 'rgba(255,255,255,0.7)'
                });
             },
        success: function (html) {
            $('#posts_content').html(html);
            $('.container-fluid').waitMe("hide");
        }
    });
}

问题是，PHP变量是动态的意味着它们并不总是在某个时间设置$description，有时只设置$hscode，有时仅$description和$hscode设置，此类型有6种组合。请在这种情况下帮助我如何发送此请求。

可能答案：

代码工作正常，但我很困惑，这是一个正确的方法，请纠正我，如果我错了，我的工作代码是：

function searchFilter(page_num) {
  page_num = page_num?page_num:0;

    $.ajax({
        type: 'POST',
        url: 'getData.php',
        data :  { page : +page_num, 
                  <?php if(isset($description)){ echo '"desc"'.' : '. "'$description'" . ',';} ?>
                  <?php if(isset($hscode)){ echo '"hscode"'.' : '. "'$hscode'" . ',';} ?>
                  <?php if(isset($from)){ echo '"from"'.' : '. "'$from'" . ',';} ?>
                  <?php if(isset($to)){ echo '"to"'.' : '. "'$to'" . ',';} ?> },


        beforeSend: function () {
            $('.container-fluid').waitMe({
                   effect : 'stretch',
                   bg : 'rgba(255,255,255,0.7)'
                });
             },
        success: function (html) {
            $('#posts_content').html(html);
            $('.container-fluid').waitMe("hide");
        }
    });
}

Answer 1

首先，您可以检查您的变量是否已设置，如果其设置已开启; y将这些变量附加到ajax数据。请尝试以下代码：

function searchFilter(page_num) {
    page_num = page_num?page_num:0;
    send_data = {};
    send_data.page = +page_num;
    <?php if (isset($description)): ?>
    send_data.desc = "<?php echo $description ?>";
    <?php endif; ?>
    <?php if (isset($hscode)): ?>
    send_data.hscode = "<?php echo $hscode ?>";
    <?php endif; ?>
    <?php if (isset($from)): ?>
    send_data.from = "<?php echo $from ?>";
    <?php endif; ?>
<?php if (isset($to)): ?>
send_data.to = "<?php echo $to ?>";
<?php endif; ?>

      $.ajax({
          type: 'POST',
          url: 'getData.php',
         data: send_data,

          beforeSend: function () {
              $('.container-fluid').waitMe({
                     effect : 'stretch',
                     bg : 'rgba(255,255,255,0.7)'
                  });
               },
          success: function (html) {
              $('#posts_content').html(html);
              $('.container-fluid').waitMe("hide");
          }
      });
}

Answer 2

为了清楚起见，在PHP中组装数组，然后使用json_encode()将其转换为JSON对象：

<?php
$php_data = [desc => $description, /* initialize other fields */];
?>
function searchFilter(page_num) {
  var data = <?php= json_encode($php_data) ?>;  /* dump as JSON object */
  data.page_num = page_num?page_num:0;          /* assign page_num field */
  $.ajax({
      type: 'POST',
      url: 'getData.php',
      data: data,                               /* pass object */

如果只是非空的话，如何通过Ajax发送php变量

2 个答案: