Question

我有一个数组

var arrList = [{ 
"email": "a@mailinator.com",
"pname": "john doe1" },
{ 
"email": "a@mailinator.com",
"pname": "john doe2" },
{ 
"email": "a@mailinator.com",
"pname": "john doe3" } ]

我想转换这个数组，并希望输出如下

{
"a@mailinator.com": [{
    "email": "a@mailinator.com",
    "pname": ["john doe1", "john doe2", "john doe3"]
}]
}

我已尝试使用lodash但未成功

arrList = _.uniqBy(arrList, "email", "pname")
result = _.chain(arrList).groupBy('email').value('')

在阵列中有多个不同的电子邮件，我们需要通过电子邮件进行分组。

Answer 1

使用_.groupBy()，然后_.map()将分组对象添加到请求的表单中：

var arrList = [{"email":"a@mailinator.com","pname":"john doe1"},{"email":"a@mailinator.com","pname":"john doe2"},{"email":"a@mailinator.com","pname":"john doe3"}];

var result = _(arrList)
  .groupBy('email')
  .map((v, email) => ({
    email,
    pname: _.map(v, 'pname')
  }))
  .value();

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.5/lodash.min.js"></script>

Answer 2

您可以使用_.chain和_.groupBy并根据您的要求创建数组。

＆＃13;

var arrList = [{ 
"email": "a@mailinator.com",
"pname": "john doe1" },
{ 
"email": "a@mailinator.com",
"pname": "john doe2" },
{ 
"email": "a@mailinator.com",
"pname": "john doe3" },
{ 
"email": "b@mailinator.com",
"pname": "b doe2" },
{ 
"email": "b@mailinator.com",
"pname": "b doe3" }]

var result=_.chain(arrList).groupBy("email").map(function(v, i) {
  return {
    email: i,
    pname: _.map(v, 'pname')
  }
}).value();
document.body.innerHTML = '<pre>' + JSON.stringify(result, null, '  ') + '</pre>';

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.13.1/lodash.min.js"></script>

＆＃13;

请运行以上代码段

Answer 3

如果你想使用核心js解决方案，那么试试这个

var arrList = [{ 
"email": "a@mailinator.com",
"pname": "john doe1" },
{ 
"email": "a@mailinator.com",
"pname": "john doe2" },
{ 
"email": "a@mailinator.com",
"pname": "john doe3" } ]

var temp = {};

for(var value of arrList){
  temp[value.email]  = temp[value.email]  || [];
  temp[value.email][0]  = temp[value.email][0]  || {};
  temp[value.email][0].pname  = temp[value.email][0].pname  || [];
  temp[value.email][0].email = value.email;
  temp[value.email][0].pname.push(value.pname);
}


console.log(JSON.stringify(temp));

与lodash的组数组

3 个答案: