Question

我有一个带有字段的模型：

@JsonDeserialize(as = DateTimeDeserializer.class)
private DateTime expiryTimeFirebaseCustomAccessToken;

使用env：

compile('com.fasterxml.jackson.datatype:jackson-datatype-joda:2.9.4')
compile('com.squareup.retrofit2:converter-jackson:2.4.0')
compile 'joda-time:joda-time:2.9.9'
compile 'com.squareup.retrofit2:retrofit:2.4.0'

和java代码：

final JodaModule jodaModule = new JodaModule();
        jodaModule.addDeserializer(DateTime.class,
                DateTimeDeserializer.forType(DateTime.class));
        jodaModule.addDeserializer(ReadableDateTime.class,
                DateTimeDeserializer.forType(ReadableDateTime.class));
        jodaModule.addDeserializer(ReadableInstant.class,
                DateTimeDeserializer.forType(ReadableInstant.class));

        final ObjectMapper objectMapper = new ObjectMapper();
        objectMapper.registerModule(jodaModule);

        Retrofit retrofit = new Retrofit.Builder()
                .baseUrl(serverAddress)                .addConverterFactory(JacksonConverterFactory.create(objectMapper))
                .build();

和json的回应：

"expiryTimeFirebaseCustomAccessToken": "2018-03-27T10:44:06.590Z"

但是，我收到了这个错误：

无法缩小类型[simple type，class org.joda.time.DateTime] 注释（值 com.fasterxml.jackson.datatype.joda.deser.DateTimeDeserializer），来自＆＃39; setExpiryTimeFirebaseCustomAccessToken＆＃39;：Class com.fasterxml.jackson.datatype.joda.deser.DateTimeDeserializer没有 [simple type，class org.joda.time.DateTime
的子类型

Answer 1

我找到了解决方案：

@JsonDeserialize(using = MyDateTimeDeserializer.class)
    private DateTime expiryTimeFirebaseCustomAccessToken;

上课：

import com.fasterxml.jackson.datatype.joda.cfg.FormatConfig;
import com.fasterxml.jackson.datatype.joda.cfg.JacksonJodaDateFormat;
import com.fasterxml.jackson.datatype.joda.deser.DateTimeDeserializer;

    import org.joda.time.DateTime;

    /**
     * Created by rudi on 3/28/18.
     */

    public class MyDateTimeDeserializer extends DateTimeDeserializer {

        public MyDateTimeDeserializer() {
            super(DateTime.class, FormatConfig.DEFAULT_DATETIME_PARSER);
        }

        public MyDateTimeDeserializer(Class<?> cls, JacksonJodaDateFormat format) {
            super(cls, format);
        }

    }

在Android中使用Retrofit进行简单类型的Joda日期时间

1 个答案: