使用三个图像上传数据时sql出错

Question

我正在尝试使用PHP和MYSQL上传三张图片和一些与汽车相关的文字。 最初，我收到消息“MYSQL已经消失......”所以我将max_packet大小增加到500M。 。数据库名称，表名都正确。

以下是我使用过的php代码。

<?php
        if(isset($_POST["submit"])) 
        {
                $check1 = getimagesize($_FILES["image1"]["tmp_name"]);
                $check2 = getimagesize($_FILES["image2"]["tmp_name"]);
                $check3 = getimagesize($_FILES["image3"]["tmp_name"]);

                if($check1 !== false and $check2 !== false and $check3 !== false)    
                {        

                    $img1 = $_FILES['image1']['tmp_name'];
                    $imgContent1 = addslashes(file_get_contents($img1));
                    $frontimg = $imgContent1;

                    $img2 = $_FILES['image2']['tmp_name'];
                    $imgContent2 = addslashes(file_get_contents($img2));
                    $backimg = $imgContent2;

                    $img3 = $_FILES['image3']['tmp_name'];
                    $imgContent3 = addslashes(file_get_contents($img3));
                    $intimg = $imgContent3;

                    $kms      = htmlentities($_POST["kms"]);
                    $make     = htmlentities($_POST["make"]);
                    $model = htmlentities($_POST["model"]);
                    $variant = htmlentities($_POST["variant"]);
                    $reg = htmlentities($_POST["year"]);
                    $color = htmlentities($_POST["color"]);
                    $owner = htmlentities($_POST["owner"]);
                    $price = htmlentities($_POST["price"]);

                    $dbHost     = 'localhost';
                    $dbUsername = 'root';
                    $dbPassword = '';
                    $dbName     = 'car';


                    $db = new mysqli($dbHost, $dbUsername, $dbPassword, $dbName);

                    // Check connection
                    if($db->connect_error)
                    {
                        die("Connection failed: " . $db->connect_error);
                    }
                    $insert = $db->query("  insert into car( frontimg, backimg, intimg, kms, make, model, variant, reg, color, owner, price ) 
                                                       values ('$frontimg', '$backimg', '$intimg','$kms','$make', '$model', '$variant', '$reg', '$color', 
                                                       '$owner','$price')  ");   

                    if($insert)
                    {

                             echo "data stored successfully";

                    }
                    else
                    {
                        echo "Check your query";
                    }   

                } 
            }
?>

php返回“检查您的查询”文本，指示SQL代码中的错误。 这里可能出了什么问题..