Laravel - 在列中的json / array中保存多个字段值

Question

我有3个表单字段name, address, profile_photo。我希望在一个列中以json / array格式保存3个字段，以便稍后在视图刀片中检索它。

我的表单看起来像这样

我试过

$customer_details= new Customer;
  {

   $profile_photo = $request->file('profile_photo');
   for ($i=0; $i < count(request('profile_photo')); $i++) {

   $pro_fileExt =  $profile_photo[$i]->getClientOriginalExtension();
   $pro_fileNameToStore = time().'.'.$pro_fileExt;

   $pro_pathToStore = public_path('images');

   Image::make($profile_photo[$i])->save($pro_pathToStore . DIRECTORY_SEPARATOR. $pro_fileNameToStore);
   $profile_ph = '/images/'.$pro_fileNameToStore; }

   $cust_details=json_encode(request(['name', 'address', $profile_ph]));
   $customer_details->details = $cust_details;
   $customer_details->save();
  }

使用此profile_photo不会保存，但其他数据保存为：

{"name":["john","Sam"],"address":["CA","FL"]}

如何保存所有字段，包括profile_photo，并在视图刀片上稍后清楚地显示每个细节？

Answer 1

希望这会对你有所帮助。

    $customer_details = new Customer;

    $profile_photo = $request->file('profile_photo');
    $profile_ph = [];

    for ($i = 0; $i < count(request('profile_photo')); $i++) {

        $pro_fileExt = $profile_photo[$i]->getClientOriginalExtension();
        $pro_fileNameToStore = time() . '.' . $pro_fileExt;

        $pro_pathToStore = public_path('images');

        Image::make($profile_photo[$i])->save($pro_pathToStore . DIRECTORY_SEPARATOR . $pro_fileNameToStore);
        $profile_ph[$i] = '/images/' . $pro_fileNameToStore;
    }

    $data = [
        'name' => $request->name,
        'address' => $request->address,
        'profile_ph' => $profile_ph
    ];

    $customer_details->details = json_encode($data);

    $customer_details->save();

如果您使用的是mysql，则details列应为text。

Answer 2

试试这个：

$names = $request->input('name');
$addresses = $request->input('address');
$profile_photos = $request->file('profile_photo');
for ($i = 0; $i < count($names); $i++) {
    $customer_details = new Customer;
    $pro_fileExt = $profile_photos[$i]->getClientOriginalExtension();
    $pro_fileNameToStore = time() . '.' . $pro_fileExt;

    $pro_pathToStore = public_path('images');

    Image::make($profile_photos[$i])->save($pro_pathToStore . DIRECTORY_SEPARATOR . $pro_fileNameToStore);
    $profile_ph = '/images/' . $pro_fileNameToStore;

    $cust_details = json_encode([
        'name' => $names[$i],
        'address' => $addresses[$i],
        'profile_photo' => $profile_ph,
    ]);

    $customer_details->details = $cust_details;
    $customer_details->save();
}

Answer 3

使用单个数据库查询尝试此操作

r.table("posts").get(1).update(
    post -> r.hashMap("views", post.g("views").add(1).default_(0))
).run(conn);