Question

在PHP中，我需要将变量传递给html输入类型标记。我怎么能通过这个？

我试图传递html标记ID，但没有发生任何事情。

这是我的mysql code：

include('db_connection.php');
if (isset($_POST['submit1'])) {
    $skills = $_POST["skills"];
}
if (isset($_POST['submit1'])) {
    $skills = $_POST["skills"];
    //print_r($skills);die;
}
$sql ="SELECT * FROM `tbl_master_property` WHERE `name` ='$skills'";
$result=$conn->query($sql);

while( $row = $result->fetch_assoc() ) { 
    $project[] = $row;
}
foreach ($project as $value) {
    $pg_address = $value['pg_address'];
    $pg_type = $value['pg_type'];
    $pg_owner = $value['pg_incharge_name'];
    $pg_mobile = $value['pg_incharge_mobile'];
    //print_r($pg_mobile);die;
}

这是我的html code：

<div class="search">
    <label>PG Name</label>
    <input type="text" id="pgname" placeholder="Search by PG Name" name="pgname" list="locations" class="searchlocation" />  
    <button type="submit1" id ="submit1" class="searchButton">
        <i class="fa fa-search searchButtonSearch"></i>
    </button>
</div>
<script>
    $(function() {
        $( "#pgname" ).autocomplete({
            source: "autocomplete.php"
        });
    });
</script>

<div class="col-lg-12 form-group">
    <label>Address</label>
    <input class="border col-lg-12" type="text" name= "address" value="<?php echo $value['pg_address']; ?>" required/>
</div>
<div class="col-lg-12 form-group">
    <label>PG Owner Name</label>
    <input class="border" type="text" name= "pg_owner" value="<?php echo $value['pg_owner ']; ?> required />
</div>

Answer 1

这有用吗？

<?php

include('db_connection.php');
if (isset($_POST['submit1'])) {
    $skills = $_POST["skills"];
}

$sql ="SELECT * FROM `tbl_master_property` WHERE `name` LIKE '%$skills%'";
$result=$conn->query($sql);

while( $row = $result->fetch_assoc() ) { 
    $project[] = $row;
}

?>

<form action="" method="post">
<div class="search">
    <label>PG Name</label>
    <input type="text" id="skills" placeholder="Search by PG Name" name="skills" list="locations" class="searchlocation" />  
    <button type="submit1" id ="submit1" class="searchButton">
        <i class="fa fa-search searchButtonSearch">Search</i>
    </button>
</div>
</form>

<?php

foreach ($project as $value) {
    $pg_address = $value['pg_address'];
    $pg_type = $value['pg_type'];
    $pg_owner = $value['pg_incharge_name'];
    $pg_mobile = $value['pg_incharge_mobile'];
    //print_r($pg_mobile);die;

?>

<script>
    $(function() {
        $( "#pgname" ).autocomplete({
            source: "autocomplete.php"
        });
    });
</script>

<div class="col-lg-12 form-group">
    <label>Address</label>
    <input class="border col-lg-12" type="text" name= "address" value="<?php echo @$value['pg_address']; ?>" required/>
</div>
<div class="col-lg-12 form-group">
    <label>PG Owner Name</label>
    <input class="border" type="text" name= "pg_owner" value="<?php echo @$value['pg_owner']; ?>" required/>
</div>

<?php } ?>

Answer 2

检查出来

 <div class="search">
   <label>PG Name</label>
   <input type="text" id="pgname" placeholder="Search by PG Name" name="pgname" list="locations" class="searchlocation" />  
   <button type="submit1" id ="submit1" class="searchButton">
     <i class="fa fa-search searchButtonSearch"></i>
  </button>
</div>
<script>
$(function() {
    $( "#pgname" ).autocomplete({
        source: "autocomplete.php"
    });
});
</script>
<div class="col-lg-12 form-group">
  <label>Address</label>
  <input class="border col-lg-12" type="text" name= "address" value="<?php if(isset( $pg_address)) echo $pg_address; ?>" required/>
  </div>
  <div class="col-lg-12 form-group">
   <label>PG Owner Name</label>
   <input class="border" type="text" name= "pg_owner" value="<?php if(isset( $pg_owner) )echo $pg_owner; ?> required />
   </div>

将php变量传递给php

2 个答案: