Question

尽可能方便地合并文件

假设我有以下降价文件

    1.md # contains 'foo'
    2.md # contains 'bar'
    3.md # 'zoo'
    4.md # 'zxc'

使用命令cat

可以轻松合并它们

$ cat {1..4}.md > merged_5.md

然而，Python需要多个步骤来实现这一结果。

创建读写方法

def read(filename):
    with open(filename) as file:
        content = file.read()
        return content
def write(filename, content):
    with open(filename, 'w') as file:
        file.write(content)

检索限定文件

import glob
filenames = glob.glob('*.md')
In [17]: filenames
Out[17]: ['1.md', '2.md', '3.md', '4.md']

阅读并合并

def combine(filenames):
    merged_conent = ""
    for filename in filenames:
        content = read(filename)
        merged_content += content
    write('merged.md', merged_content)

在main模块中封装数据和方法，另存为＆＃39; combine_files.py＆＃39;

def main():
    filenames = glob.glob('*.md')
    combine(filenames)

if __name__ == '__main__':
    main()

在命令行上运行

python3 combine_files.py

它并不像命令“猫”那样方便。

如何重构代码以尽可能方便？

Answer 1

怎么样？：

def fun1():
    mysum = 0
    def fun2(arg):
        mysum += arg
    fun2(1)
    fun2(2)
    fun2(3)
    print mysum

Answer 2

如何轻松做到：

def cat(out, *src):
    '''Concatenate files'''

    with open(out, 'wb') as f:
        data = b'\n'.join(open(i, 'rb').read() for i in src)
        f.write(data)

您现在可以使用cat('merged.md', glob.glob('*.md'))来呼叫它。怎么样方便？当然比GNU Coreutils的来源容易得多。

尽可能方便地合并文件

2 个答案: