Question

目标：
当您启动Android应用程序时，该按钮不应在5秒后显示。

问题：
代码不起作用，我错过了哪一部分？

的信息：
*我是android的新手 *代码的灵感来自此页Android - Hide button during an onClick action

谢谢！

public class MainActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        Button button2 = (Button) findViewById(R.id.btn_test);
        button2.setVisibility(GONE);

        new Thread(new Runnable() {
            @Override
            public void run() {

                try
                {
                    //dummy delay for 5 second
                    Thread.sleep(5000);
                }
                catch (InterruptedException e)
                {
                    e.printStackTrace();
                }


                runOnUiThread(new Runnable() { //resetting the visibility of the button
                    @Override
                    public void run() {

                        //manipulating UI components from outside of the UI Thread require a call to runOnUiThread
                        button2.setVisibility(VISIBLE);
                    }
                });
            }
        }).start();


    }

}

Answer 1

这可以通过更简单的方式实现。如果您需要的序列是：启动应用 - ＆gt;显示按钮 - ＆gt;等待5秒 - ＆gt;隐藏按钮

final Button button2 = (Button) findViewById(R.id.btn_test);

    button2.postDelayed(new Runnable() {
        @Override
        public void run() {
            if (!isDestroyed() && !isFinishing()) {
                button2.setVisibility(View.GONE);
            }
        }
    },5000);

否则，如果您应在应用启动后5秒钟后显示按钮，则只需将按钮的展示位置设置为布局中的GONE，然后将button2.setVisibility(View.GONE)更改为button2.setVisibility(View.VISIBLE)内置延迟后的操作< / p>

Answer 2

你需要设置一个监听器来启动命令，onCreate就是创建。

public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    final Button button2 = (Button) findViewById(R.id.btn_test);


    button2.setOnClickListener(new OnClickListener() {
       @Override
       public void onClick(View v) {
       button2.setVisibility(GONE);
    new Thread(new Runnable() {
        @Override
        public void run() {

            try
            {
                //dummy delay for 5 second
                Thread.sleep(5000);
            }
            catch (InterruptedException e)
            {
                e.printStackTrace();
            }


            runOnUiThread(new Runnable() { //resetting the visibility of the button
                @Override
                public void run() {

                    //manipulating UI components from outside of the UI Thread require a call to runOnUiThread
                    button2.setVisibility(VISIBLE);
                }
            });
        }
    }).start();
    }

此代码将隐藏按钮AFTER onClick，启动线程，5秒后它将再次出现。

显示非活动按钮5秒钟

2 个答案: