Question

我一直在使用c＃：

获取文件和文件夹

static IEnumerable<string> GetFiles(string path)
        {
            Queue<string> queue = new Queue<string>();
            queue.Enqueue(path);
            while (queue.Count > 0)
            {
                path = queue.Dequeue();
                try
                {
                    foreach (string subDir in Directory.GetDirectories(path))
                    {
                        queue.Enqueue(subDir);
                    }
                }
                catch (Exception ex)
                {
                    Console.Error.WriteLine(ex);
                }
                string[] files = null;
                try
                {
                    files = Directory.GetFiles(path);
                }
                catch (Exception ex)
                {
                    Console.Error.WriteLine(ex);
                }
                if (files != null)
                {
                    for (int i = 0; i < files.Length; i++)
                    {
                        yield return files[i];
                    }
                }
            }
        }

然后我在控制台输出了输出，分别是这样的：

static void Main(string[] args)
        {
                     foreach (string file in GetFiles("C:\\"))
            {
                Console.WriteLine(file);

            }
            Console.ReadLine();
        }

所以...我需要将其序列化为带有条件的XML文件（长度小于8的文件夹和文件，扩展名为3个字符）。目前条件并不重要。在阅读了很多有用的东西之后，我找不到合适的解决方案。问候。

Answer 1

我在1月份写过代码。看看这是否有帮助

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.IO;

namespace WriteFileNamesXml
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        const string FOLDER = @"c:\temp";
        static XmlWriter writer = null;
        static void Main(string[] args)
        {
            XmlWriterSettings settings = new XmlWriterSettings();
            settings.Indent = true;

            writer = XmlWriter.Create(FILENAME, settings);
            writer.WriteStartDocument(true);

            DirectoryInfo info = new DirectoryInfo(FOLDER);
            WriteTree(info);

            writer.WriteEndDocument();
            writer.Flush();
            writer.Close();


        }
        static long WriteTree(DirectoryInfo info)
        {
            long size = 0;
            writer.WriteStartElement("Folder");
            try
            {
                writer.WriteAttributeString("name", info.Name);
                writer.WriteAttributeString("numberSubFolders", info.GetDirectories().Count().ToString());
                writer.WriteAttributeString("numberFiles", info.GetFiles().Count().ToString());
                writer.WriteAttributeString("date", info.LastWriteTime.ToString());


                foreach (DirectoryInfo childInfo in info.GetDirectories())
                {
                    size += WriteTree(childInfo);
                }

            }
            catch (Exception ex)
            {
                string errorMsg = string.Format("Exception Folder : {0}, Error : {1}", info.FullName, ex.Message);
                Console.WriteLine(errorMsg);
                writer.WriteElementString("Error", errorMsg);
            }

            FileInfo[] fileInfo = null;
            try
            {
                fileInfo = info.GetFiles();
            }
            catch (Exception ex)
            {
                string errorMsg = string.Format("Exception FileInfo : {0}, Error : {1}", info.FullName, ex.Message);
                Console.WriteLine(errorMsg);
                writer.WriteElementString("Error", errorMsg);
            }

            if (fileInfo != null)
            {
                foreach (FileInfo finfo in fileInfo)
                {
                    try
                    {
                        writer.WriteStartElement("File");
                        writer.WriteAttributeString("name", finfo.Name);
                        writer.WriteAttributeString("size", finfo.Length.ToString());
                        writer.WriteAttributeString("date", info.LastWriteTime.ToString());
                        writer.WriteEndElement();
                        size += finfo.Length;
                    }
                    catch (Exception ex)
                    {
                        string errorMsg = string.Format("Exception File : {0}, Error : {1}", finfo.FullName, ex.Message);
                        Console.WriteLine(errorMsg);
                        writer.WriteElementString("Error", errorMsg);
                    }
                }
            }

            writer.WriteElementString("size", size.ToString());
            writer.WriteEndElement();
            return size;

        }
    }
}

使用c＃以XML格式序列化获取的文件夹和文件的最佳方法

1 个答案: