我在keyvalue对上使用聚合时遇到了一些困难。这甚至可能吗？或者我是否必须重写结构以获得更具体的命名字段？
给出以下对象
[ElasticsearchType(IdProperty = "ProductIDRemote")]
public class Product
{
public string UrlID { get; set; }
public string ProductIDRemote { get; set; }
public DateTime Created { get; set; }
public DateTime Modified { get; set; }
public string ProductName { get; set; }
public string ProductDescription { get; set; }
public List<ProductShop> Shops { get; set; }
public List<FeatureGroup> FeatureGroups { get; set; }
public List<Feature> Properties { get; set; }
public string DefaultImage { get; set; }
public List<Image> Images { get; set; }
public List<Document> Documents { get; set; }
public List<String> EANs { get; set; }
public string Supplier { get; set; }
public List<string> Labels { get; set; }
public DateTime? EndDate { get; set; }
public List<String> Categories { get; set; } = new List<string>();
}
public class ProductShop
{
public string ShopName { get; set; }
public decimal? Price { get; set; }
public decimal? PriceFrom { get; set; }
public decimal ShippingCosts { get; set; }
public string DeliveryTime { get; set; }
public string LinkABC { get; set; }
public string LinkCP { get; set; }
//public string Stock { get;set }
}
public class FeatureGroup
{
public string Name { get; set; }
public List<Feature> Features { get; set; }
}
public class Feature
{
public string Name { get; set; }
public string Value { get; set; }
}
我可以使用以下查询获取不同的商店。
var response = client.Search<Product>
(s => s
.Query(
q =>
q.Bool(
b => b.Must(
m => m.Term(t => t.Field(f => f.Labels).Value(testlabel))
)
)
)
.Size(100)
.Aggregations(a => a
.Terms("shops", st => st.Field(f => f.Shops.First().ShopName.Suffix("keyword")).Size(100).Order(o => o.CountDescending()))
.Terms("categories", st => st.Field(f => f.Categories.First().Suffix("keyword")))
.Terms("brands",
b => b.Field(f => f.Properties.Where(p => p.Name == "brand").First().Value.Suffix("keyword")))
.Terms("featuregroups", fg => fg.Field(f => f.FeatureGroups.First().Suffix("keyword"))
.Aggregations(sa =>
sa.Terms("feature", ft => ft.Field(f => f.FeatureGroups.First().Features.First().Name.Suffix("keyword")))))
)
);
return response;
但我仍然坚持通过类似品牌的键来进行物业过滤的混合。
如果成功，我将尝试获取按功能组分组的功能。
根据要求提供示例产品
{
"took": 18,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"skipped": 0,
"failed": 0
},
"hits": {
"total": 3,
"max_score": 13.978779,
"hits": [
{
"_index": "catalog_nl",
"_type": "product",
"_id": "0001",
"_score": 13.978779,
"_source": {
"productIDRemote": "0001",
"created": "0001-01-01T00:00:00",
"modified": "0001-01-01T00:00:00",
"productName": "Dummy product 001",
"productDescription": "tralalalal",
"featureGroups": [
{
"name": "Dimensions",
"features": [
{
"name": "Length",
"value": "1m"
},
{
"name": "Width",
"value": "1m"
},
{
"name": "Heigth",
"value": "2m"
}
]
},
{
"name": "Dummy",
"features": [
{
"name": "Length",
"value": "10m"
},
{
"name": "Width",
"value": "10m"
},
{
"name": "Heigth",
"value": "1m"
}
]
}
],
"properties": [
{
"name": "brand",
"value": "brandname1"
},
{
"name": "property2",
"value": "property 2 value"
}
],
"categories": []
}
}
]
}
}
我想要做的是获取名称字段为＆＃39;品牌＆＃39;的属性的聚合。 。我不确定这是不是正确的方法。或者定义品牌字段并在该字段上汇总
由于我导入了许多不同的属性，因此键值对更容易，而不是定义多个字段。
我还想要在功能组和功能上进行嵌套聚合，而不是按特定功能名称进行过滤。 所以给定一组产品，它们具有哪些功能。这些功能按功能组分组
Dimension
length
width
height
修正了第1部分！
通过以下json，我获得了品牌。小记。我必须使用嵌套聚合，所以我必须将properties属性更改为[Nested]
POST catalog_nl/product/_search
{
"from": 0,
"size": 12,
"aggs": {
"nested_tags": {
"nested": {
"path": "properties"
},
"aggs": {
"properties": {
"filter": {
"term": {
"properties.name": "brand"
}
},
"aggs": {
"tags_name_terms": {
"terms": {
"field": "properties.name.keyword"
}
},
"tags_value_terms": {
"terms": {
"field": "properties.value.keyword"
}
}
}
}
}
}
}
}
返回以下内容：
{
"took": 771,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"skipped": 0,
"failed": 0
},
"hits": {
"total": 668858,
"max_score": 0,
"hits": []
},
"aggregations": {
"nested_tags": {
"doc_count": 1016645,
"properties": {
"doc_count": 397242,
"tags_name_terms": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "brand",
"doc_count": 397242
}
]
},
"tags_value_terms": {
"doc_count_error_upper_bound": 1393,
"sum_other_doc_count": 358172,
"buckets": [
{
"key": "Noppies",
"doc_count": 6288
},
{
"key": "name it",
"doc_count": 5474
},
{
"key": "Tumble 'N Dry",
"doc_count": 4881
},
{
"key": "Blue Seven",
"doc_count": 4588
},
{
"key": "Merkloos",
"doc_count": 3746
},
{
"key": "Dirkje",
"doc_count": 2915
},
{
"key": "NIKE",
"doc_count": 2873
},
{
"key": "Disney",
"doc_count": 2796
},
{
"key": "ADIDAS",
"doc_count": 2772
},
{
"key": "Difuzed",
"doc_count": 2737
}
]
}
}
}
}
}
现在找出c＃代码来获取此请求。