从外部Windows命令实用程序捕获异常

Question

我正在尝试在运行外部命令时终止脚本导致错误。考虑一下这个简单的代码：

try {
    where.exe Test-App
}

catch {
    Write-Error "Exception caught." -ErrorAction Continue
    throw
}

Write-Host "Test message!"

输出：

where.exe : INFO: Could not find files for the given pattern(s).
At line:2 char:5
    where.exe Test-App
...
Test message!

当外部命令导致错误时，是否可以进入catch块并抛出？

期望的输出：

C:\Scripts\Test-Script.ps1 : Exception caught.

Answer 1

作为TheIncorrigible1 suggests，请检查$LASTEXITCODE，如下所示：

$where = where.exe test 2>&1
if($LASTEXITCODE -ne 0){
    throw "Exception caught."
    return
}
# otherwise continue, grab actual output from $where