Question

from bokeh.core.state import State
from bokeh.io import _CommsHandle, push_notebook
 from bokeh.embed import notebook_div


        ModuleNotFoundError                       Traceback (most recent call last)
        <ipython-input-4-b18f604973b2> in <module>()
        ----> 1 from bokeh.core.state import State
              2 from bokeh.io import _CommsHandle, push_notebook
              3 from bokeh.embed import notebook_div



        ModuleNotFoundError: No module named 'bokeh.core.state'


from add_on import output_notebook, show_figure
from bokeh.io import output_notebook 
from bokeh.plotting import Figure
from bokeh.models import ColumnDataSource


output_notebook()

bokeh.core.state导入状态是唯一无效的导入。 python版本是相同的，名称中没有散景的文件。任何人都知道最新情况吗？

仅供参考：我正在尝试创建一个散景图，我可以用套索选择数据点并将它们放回到jupyter笔记本中进行分析。这是我创建图表的代码，非常喜欢获取数据点的一些见解（假设使用Javascript）。

    import matplotlib as mpl

    import bokeh.plotting as bpl
    import bokeh.models as bmo

    from bokeh.models import CategoricalColorMapper, ContinuousColorMapper


    TOOLS="hover,crosshair,pan,wheel_zoom,zoom_in,zoom_out,box_zoom,undo,redo,reset,tap,save,box_select,poly_select,lasso_select,"

    def graph_bokeh(algorithm,coordinate_df,metric):


        source = bpl.ColumnDataSource(coordinate_df)

    #     color_map = bmo.CategoricalColorMapper(factors=coordinate_df[metric].unique())

    #     colors = {1:'red',0:'grey'}
        if metric != 'LengthOfStayDaysNBR':
            color_mapper = CategoricalColorMapper(palette=['red','grey'])#,factors = metric)
        else:
            color_mapper = ContinuousColorMapper(palette='Magma256', low=min(coordinate_df[metric]), high=max(coordinate_df[metric]))




        bokeh_graph = figure(width=250, height = 250, title = '{}'.format(str(algorithm)[:3]),tools=TOOLS)

        bokeh_graph.scatter('x-{}'.format(str(algorithm)[:3]),'y-{}'.format(str(algorithm)[:3])\
                            ,color={'field': metric,'transform': color_mapper}\
                            , legend = metric, source = source)



        return bokeh_graph




    for metric in metrics:

        bokeh_graphs = {}
        for i,algorithm in enumerate(algorithms):


             bokeh_graphs[i+1] = graph_bokeh(algorithm,df_algs,metric)

    graph_list = []
    for k,v in bokeh_graphs.items():

        if k%2 == 1 and k!= len(bokeh_graphs):
            graph_list.append([bokeh_graphs[k],bokeh_graphs[k+1]])
        elif k%2 == 1 and k == len(bokeh_graphs):
            graph_list.append([bokeh_graphs[k],None])

    p = gridplot(graph_list)
    show(p)

（对不起三/四部分问题）：我在使用lengthofstay指标的颜色渐变时遇到问题（第三列我想用x / y坐标着色）

        color_mapper = ContinuousColorMapper(palette='Magma256', low=min(coordinate_df[metric]), high=max(coordinate_df[metric]))

总是输出蓝色渐变（无论我指定什么调色板）

最后，图表在Internet Explorer中打开，我想要chrome。

import webbrowser

webbrowser.register（“chrome”，无）

似乎没有用，

也没有显示（浏览器= '铬'）

Answer 1

该模块不久前移至bokeh.io：

In [3]: from bokeh.io.state import State

In [4]:

我可以问你为什么认为你需要直接使用State吗？对于普通用户来说，这并不是我真正认为必需的东西。它主要用于促进测试。

散景错误：导入错误，颜色渐变错误，JS反馈和浏览器选择

1 个答案: