Question

我创建了一个附带loginViewController.swift的简单登录屏幕。我有简单的登录api。它在post man web服务上显示响应的web服务没有使用alamofire在xcode上显示序列化的json输出。如何从url获取序列化json。

et url="http://192.169.201.32:9000//users/authenticate"  ?the api is getting two parameters from username ="andrews" and password="admin2".

       let url="http://192.168.100.11:9000//users/authenticate"
    override func viewDidLoad() {
        super.viewDidLoad()

        Alamofire.request(url, method: .post, parameters:["username":"andrews","password":"admin2"], encoding: JSONEncoding.default)
            .responseJSON { response in          
/////is it correct way to enter the parameter??
                print("abcsign in")
                print(response)
                //to get status code
                if let status = response.response?.statusCode {
                    switch(status){
                    case 201:
                        print("example success")
                    default:
                        print("error with response status: \(status)")
                    }
                }
                //to get JSON return value
                if let result = response.result.value {
                    let JSON = result as! NSDictionary
                     print("abcsign in 2")
                    print(JSON)

                }

        }
        [self  .boaderSetting()]


        username_input.text = "andrews"
        password_input.text = "admin2"

        [self .login_now(username:"andrews", password:"admin2")]
        let preferences = UserDefaults.standard
        if preferences.object(forKey: "session") != nil
        {
            login_session = preferences.object(forKey: "session") as! String
            check_session()
        }
        else
        {
            LoginToDo()
        }


    }

如何将序列化的json输出到Ns日志？你可以从这个链接下载项目。https://drive.google.com/file/d/1h3TMFkpyOdCB_SoLYdca5Jmh4vulL7t_/view?usp=sharing

Answer 1

使用URLEncoding代替JSONEncoding将解决您的问题

api没有使用alamofire显示序列化的json输出

1 个答案: