Question

我的网页中有三个文本框，使用html5 datalist标记自动完成。现在，我想在用户点击搜索按钮时显示搜索结果。

如何获取所有三个文本框字段值并在一个sql查询中搜索以在另一个页面中取消相似的结果..

HTML：

<form class="tg-formtheme tg-formsearch">
<fieldset>
    <legend>Search Thousands of verified bussiness</legend>
    <div class="form-group">
        <input type="text" name="keyword" class="form-control" list="city" placeholder="Enter city">
    </div>
    <datalist id="city">
              <option value="Bangalore">
              <option value="hyderabad">
                  <option value="mumbai">
              <option value="pune">
              <option value="chennai">
              <option value="kolkata">
              <option value="jaipur">
              <option value="delhi">
              <option value="kanput">
              <option value="indore">
              <option value="patna">
              <option value="mysore">
    </datalist>
    <div class="form-group">
        <input type="text" name="keyword" class="form-control" list="location" placeholder="Enter location">
    </div>
    <datalist id="location">
              <option value="Marathahalli">
              <option value="BTM Layout">
                  <option value="HSR Layout">
              <option value="Banashankari">
              <option value="Basavanagudi">
              <option value="Domlur">
              <option value="Jayanagar">
              <option value="Koramangala">
              <option value="Rajajinagar">
              <option value="Sadashivanagar">
              <option value="Nagarbhavi">
              <option value="Whitefield">
    </datalist>
    <div class="form-group">
        <input type="text" name="keyword" class="form-control" placeholder="select Category">
    </div>

    <div class="tg-btns">
        <button class="tg-btn" type="submit">Search Now</button>
        <button class="tg-btn" type="submit">Reset all</button>
    </div>
</fieldset>
</form>

PHP

 if(isset($_POST['search'])){


$city = trim($_POST['city']);
$location = trim($_POST['location']);
$category  = trim($_POST['category']);



  $stmt = $search->runQuery("SELECT * FROM jposts WHERE city LIKE %'.$city.'% OR location LIKE %'.$location.'% OR business_name LIKE %'.$category.'%");
 $stmt->execute();

    while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {

        extract($row);
        echo $row['city'] . "<br>";
        echo $row['business_name'];
        echo $row['address'];

 }

提交数据后，我收到以下错误：

Fatal error: Uncaught PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '%'. tirupati .'% OR location LIKE %'. amnagar .'% OR business_name LIKE %'. maci' at line 1 in C:\xampp\htdocs\justshow.in\index.php:20 Stack trace: #0 C:\xampp\htdocs\justshow.in\index.php(20): PDOStatement->execute() #1 {main} thrown in C:\xampp\htdocs\justshow.in\index.php on line 20

Answer 1

使用LIKE - 运算符在查询中出现语法错误。你必须在引号中使用precent-char，如下所示：

"... WHERE city LIKE '%".$city."' OR ...

最终的查询应如下所示：

... WHERE city LIKE '%mumbai' OR ...

查看this链接，了解有关LIKE的更多信息。

Answer 2

您的刻度线未正确放置。试试这个：

 $stmt = $search->runQuery("SELECT * FROM jposts WHERE city LIKE '%".$city."%' 
  OR location LIKE '%".$location."%' OR business_name LIKE 
 '%".$category."%'");

SQL-Query中抛出错误

2 个答案: