Question

我想获得每位员工的总工作时数。数据的详细信息如下：

每位用户每天有两个条目，第一个条目是登录时间第二个条目是注销时间。
有些用户可能没有日常用户。

我想要一周中每位用户的总工作时数。

以上是数据的屏幕截图。我想在新表中获得每个用户的总工作时数。我该如何实现？

Answer 1

因为您只提取了两个值，所以您可以按用户ID（我假设是ClockNo）和日期进行分组，然后使用MIN和MAX函数来拉取开始和结束时间每一天。获得间隔后，您可以按用户总结结果。

SELECT
    ClockNo
,   MIN( FirstName ) AS FirstName
,   MIN( LastName ) AS LastName
,   SUM( [Hours] ) AS TotalHours
FROM
    (
        SELECT
            ClockNo
        ,   MIN( FirstName ) AS FirstName
        ,   MIN( LastName ) AS LastName
        ,   [Date]
        -- Not sure what the time format is, you'll need to adjust this
        ,   COALESCE( MAX( [Time] ) - MIN( [Time] ), 0 ) AS [Hours] 
        FROM
            ClockTable
        GROUP BY
            ClockNo, [Date]
    ) AS HoursPerDay
GROUP BY
    ClockNo

Answer 2

首先要做的是将整数DATE和TIME数据转换为可以CONVERT到DATETIME或TIME数据类型的格式，这样您就可以执行DATE函数，如DATEDIFF，反对

整数DATE到DATETIME数据类型

DECLARE @date INT = 20180320
SELECT CONVERT(DATETIME, CAST(@Date AS CHAR(8)), 101)

2018-03-20 00：00：00.000

DECLARE @time INT = 215319
SELECT  RIGHT(
            CAST(DATEADD(HOUR, (@Time / 1000000) % 100,
                    DATEADD(MINUTE, (@Time / 10000) % 100,
                        DATEADD(SECOND, (@Time / 100) % 100, CAST('00:00:00' AS TIME(2)) ) ) )
                AS NVARCHAR(16))
            , 8)

21：53.00

然后使用派生表LEAD

组合批次

DECLARE @t TABLE ( ClockNo INT, FirstName NVARCHAR(50), LastName NVARCHAR(50), [Date] INT, [Time] INT)

INSERT INTO @t(
      ClockNo
    , FirstName
    , LastName
    , [Date]
    , [Time]
)
SELECT 111, 'J', 'Doe', 20180320, 80620     UNION ALL
SELECT 111, 'J', 'Doe', 20180320, 170124    UNION ALL
SELECT 111, 'J', 'Doe', 20180322, 75436     UNION ALL
SELECT 111, 'J', 'Doe', 20180322, 120854    UNION ALL
SELECT 132, 'S', 'Doe', 20180319, 134630    UNION ALL
SELECT 132, 'S', 'Doe', 20180319, 215319    UNION ALL
SELECT 132, 'S', 'Doe', 20180320, 134630    UNION ALL
SELECT 132, 'S', 'Doe', 20180320, 215319

SELECT X.ClockNo
     , X.FirstName
     , X.LastName
     , TotalHours = CONVERT(VARCHAR, DATEADD(MILLISECOND, SUM(DATEDIFF(SECOND, X.LogOn , X.LogOff)) * 1000, 0), 114)
FROM(
        SELECT 
              T.ClockNo
            , T.FirstName
            , T.LastName
            , T.[Date]
            , LogOn     = CAST(
                                        CAST(T.[Date] AS CHAR(8)) + ' ' + RIGHT(
                                                                            CAST(DATEADD(HOUR, (T.[Time] / 1000000) % 100,
                                                                                    DATEADD(MINUTE, (T.[Time] / 10000) % 100,
                                                                                        DATEADD(SECOND, (T.[Time] / 100) % 100, CAST('00:00:00' AS TIME(2)) ) ) )
                                                                                AS NVARCHAR(16))
                                                                            , 8)
                                        AS DATETIME)

            , LogOff = CAST(LEAD(
                                CAST(T.[Date] AS CHAR(8)) + ' ' + RIGHT(
                                                                        CAST(DATEADD(HOUR, (T.[Time] / 1000000) % 100,
                                                                            DATEADD(MINUTE, (T.[Time] / 10000) % 100,
                                                                                DATEADD(SECOND, (T.[Time] / 100) % 100, CAST('00:00:00' AS TIME(2)) ) ) )
                                                                            AS NVARCHAR(16))
                                                                        , 8)
                                )
                                OVER
                                    (   PARTITION BY T.ClockNo, T.[Date] 
                                        ORDER BY T.[Date], T.[Time]
                                    )
                        AS DATETIME )
        FROM 
            @t T
) X
GROUP BY
      X.ClockNo
    , X.FirstName
    , X.LastName

返回

ClockNo FirstName   LastName    TotalHours

111     J           Doe         13:09:00:000

132     S           Doe         16:14:00:000

警告 - 解决方案仅在LogOn和LogOff在同一天发生时才有效

如何确定多个条目的总小时数

2 个答案: