Question

JSON数组如下

[{"id":"26","buName":"CAS","totFocCust":23,"totCustResp":10,"totFocProj":160,"totProjResp":13,"wtProjScore":1076.65,"teamSize":246},{"id":"33","buName":"ECO","totFocCust":0,"totCustResp":0,"totFocProj":0,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"28","buName":"DAS","totFocCust":0,"totCustResp":0,"totFocProj":0,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"27","buName":"DCS","totFocCust":9,"totCustResp":0,"totFocProj":31,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"29","buName":"EAS","totFocCust":24,"totCustResp":4,"totFocProj":114,"totProjResp":5,"wtProjScore":434.83,"teamSize":89},{"id":"30","buName":"IMS","totFocCust":9,"totCustResp":0,"totFocProj":25,"totProjResp":0,"wtProjScore":0,"teamSize":0}]

我需要添加wtProjScore和teamSize的值，其中buName是CAS，EAS和DAS，并将它与其他buName一起显示在同一个数组中，例如。如下所示。使用angularJS迭代JSON数组。

[{"id":"2689","buName":"ABS","totFocCust":23,"totCustResp":10,"totFocProj":160,"totProjResp":13,"wtProjScore":1511.48,"teamSize":335},{"id":"33","buName":"CISCO","totFocCust":0,"totCustResp":0,"totFocProj":0,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"27","buName":"DCS","totFocCust":9,"totCustResp":0,"totFocProj":31,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"30","buName":"IMS","totFocCust":9,"totCustResp":0,"totFocProj":25,"totProjResp":0,"wtProjScore":0,"teamSize":0}]

Answer 1

您可以使用JavaScript filter和reduce来完成此任务：

a = [{"id":"26","buName":"CAS","totFocCust":23,"totCustResp":10,"totFocProj":160,"totProjResp":13,"wtProjScore":1076.65,"teamSize":246},{"id":"33","buName":"ECO","totFocCust":0,"totCustResp":0,"totFocProj":0,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"28","buName":"DAS","totFocCust":0,"totCustResp":0,"totFocProj":0,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"27","buName":"DCS","totFocCust":9,"totCustResp":0,"totFocProj":31,"totProjResp":0,"wtProjScore":0,"teamSize":0},{"id":"29","buName":"EAS","totFocCust":24,"totCustResp":4,"totFocProj":114,"totProjResp":5,"wtProjScore":434.83,"teamSize":89},{"id":"30","buName":"IMS","totFocCust":9,"totCustResp":0,"totFocProj":25,"totProjResp":0,"wtProjScore":0,"teamSize":0}]

function check(x){
  return x.buName == "CAS" || x.buName == "EAS" || x.buName == "DAS";
}
b = a.filter((x)=>{return check(x)})

c = b.reduce((x,y)=>{return x+y.wtProjScore},0)

d = b.reduce((x,y)=>{return x+y.teamSize},0)

console.log("For CAS, EAS, DAS:")
console.log("Total wtProjScore: ",c)
console.log("Total teamSize: ",d)

如果您希望以不同方式呈现您的要求，请说明您的要求。或者您可以根据需要自行调整此代码

Answer 2

您可以使用简单的var totprojScore = totTeamSize = 0; $scope.newJSONArray = []; //Use this to bind your view. yourJSONArray.forEach(function(obj) { if(obj.buName == "CAS" || obj.buName == "EAS" || obj.buName == "DAS"){ totprojScore += obj.wtProjScore ; totTeamSize += obj.teamSize; } else{ $scope.newJSONArray.push(obj); } }); $scope.newJSONArray.push({ "id":temp, "buName":"tempName", "wtProjScore":totprojScore , "teamSize":totTeamSize });循环来实现此目的。

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添加JSON数组的值并在条件下显示在一个数组下

2 个答案: