Question

我有一个对象，我希望根据两个键进行分组。

var obj = [{
  make: "nissan",
  model: "sunny",
  colour: "red"
},
{
  make: "nissan",
  model: "sunny",
  colour: "red"
},
{
  make: "nissan",
  model: "sunny",
  colour: "red1"
}];

var result = _.groupBy(obj, p=>p.model);

给了我一个结果。

我希望这是基于模型和颜色的组，所以我有两个结果：

result =  [{
  make: "nissan",
  model: "sunny",
  colour: "red"
},
{
  make: "nissan",
  model: "sunny",
  colour: "red"
}];

如何借助Underscore js或任何其他简短的方法来做到这一点。

Answer 1

使用underscore.js groupBy，您可以对多个属性进行分组：

const obj = [{make: "nissan",model: "sunny",colour: "red"}, {make: "nissan",model: "sunny",colour: "red"},{make: "nissan",model: "sunny",colour: "red1"}];
const result = _.groupBy(obj, item => item.model + '#' + item.colour);

console.log(result);

<script src="//cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore.js"></script>

但您在问题中显示的result似乎是Array.prototype.filter()：

const obj = [{make: "nissan",model: "sunny",colour: "red"}, {make: "nissan",model: "sunny",colour: "red"},{make: "nissan",model: "sunny",colour: "red1"}];
const result = obj.filter(item => item.model === 'sunny' && item.colour === 'red');

console.log(result);

Answer 2

因为你问过＆＃34; 如何在Underscore js或任何其他简短方法的帮助下做到这一点＆＃34; ，这是使用Array.prototype.filter()

的简短方法

＆＃13;

 var obj = [{
        make: "nissan",
        model: "sunny",
        colour: "red"
    },{
        make: "nissan",
        model: "sunny",
        colour: "red"
    },
    {
        make: "nissan",
        model: "sunny",
        colour: "red1"
    }];
    
    var res = obj.filter( key => key.colour === "red")
    console.log(res)

＆＃13;

Answer 3

var result = _.groupBy(obj, function(o){
    return o.model + o.color;
});

GroupBy项目使用基于两个键的下划线

3 个答案: