我以为我之前有这个工作但是,即使在使webstorm的缓存无效之后,这仍然无效。就像标题所说,我在下面的陈述中无法击中任何断点。我在某处读到语句" 是一个赋值表达式,并且该函数没有在帧中调用,所以没有什么可以进入int o"。有没有办法重写这个,以便我可以调试?
const request = require('request');
const Feed = require('../models/feed');
const async = require('async');
const FeedParser = require('feedparser');
const {check, validationResult} = require('express-validator/check');
const {sanitizeParam} = require('express-validator/filter');
const feedParserOptions = {addmeta: 'false'};
const authorEndpoint = 'http://localhost:3000/authors/';
const debug = require('debug');
exports.createAuthor = [
check('firstName', 'First name must be specified').isLength({min: 1}).trim(),
check('lastName', 'Last name must be specified').isLength({min: 1}).trim(),
sanitizeParam('firstName').trim().escape(),
sanitizeParam('lastName').trim().escape(),
(req, res, next) => {
const errors = validationResult(req);
const author = new Author({
firstName: req.query.firstName,
lastName: req.query.lastName,
});
debug(req.query.firstName);
if (errors.isEmpty()) {
let query = {
$or: [{firstName: {$regex: req.query.firstName, $options: 'i'}},
{lastName: {$regex: req.query.lastName, $options: 'i'}}],
}; // TODO this regex fails if a parameter is missing.
Author.findOne(query).sort([['lastName', 'ascending']]).exec((err, existingAuthor) => {
if (err) {
return next(err);
}
if (!(existingAuthor == null)) {
let result = {status: 'Author already exists: ', author_id: String(existingAuthor.id)};
res.locals.messages = result;
next();
} else if (existingAuthor == null) {
author.save(function(err, newAuthor) {
if (err) {
return next(err);
}
let result = {status: 'New author saved', author_id: String(newAuthor.id)};
res.locals.messages = result;
next();
});
}
});
}
},
];