Question

我的反应应用程序中有一个Reactstrap模式。我希望只要不使用Modal就可以卸载它。

Modal在docs示例中的工作方式，它只是隐藏，但Modal仍然被挂载。

如何在用户关闭Modal时卸载Modal？

import React from 'react';
import { Button, Modal, ModalHeader, ModalBody, ModalFooter } from 'reactstrap';

class ModalExample extends React.Component {
  constructor(props) {
    super(props);
    this.state = {
      modal: false
    };

    this.toggle = this.toggle.bind(this);
  }

  toggle() {
    this.setState({
      modal: !this.state.modal
    });
  }

  render() {
    return (
      <div>
        <Button color="danger" onClick={this.toggle}>{this.props.buttonLabel}</Button>
        <Modal isOpen={this.state.modal} toggle={this.toggle} className={this.props.className}>
          <ModalHeader toggle={this.toggle}>Modal title</ModalHeader>
          <ModalBody>
            Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.
          </ModalBody>
          <ModalFooter>
            <Button color="primary" onClick={this.toggle}>Do Something</Button>{' '}
            <Button color="secondary" onClick={this.toggle}>Cancel</Button>
          </ModalFooter>
        </Modal>
      </div>
    );
  }
}

export default ModalExample;

Answer 1

在std::shared_ptr<T> pop() { std::lock_guard<std::mutex> lock(m); if(data.empty()) throw empty_stack(); // data.pop(); will remove top element return std::make_shared<T>(std::move(data.top())); // top element has not changed }内，根据render()值，可选择渲染模式。

this.state.modal

Reactstrap Modal在关闭时卸载

1 个答案: