执行以下查询以查找重复的
select * from (
select a.* ,count (*) over (partition by a.ID) as tot
from HREMP a
) tt
where tt.tot >1
返回423行,
我执行了另一个查询来查找非重复记录
select * from (
select a.* ,count (*) over (partition by a.ID) as tot
from HREMP a
) tt
where tt.tot =1
返回685条记录
我发现423个副本中有196个不同的记录 现在,如何从重复记录中选择第一条记录?
答案 0 :(得分:5)
select distinct *
from ( select a.*, count(*) over (partition by a.ID) as tot
from HREMP a
) tt
where tt.tot > 1
或
select *
from ( select a.*
, count(*) over (partition by a.ID) as tot
, row_number() over (partition by a.ID order by 1) as rn
from HREMP a
) tt
where tt.tot > 1
and tt.rn = 1