我的代码根据以下代码创建了一个新工作表ws2
,其中我有一个从ws1
中提取的表格。我想将一个数据透视表放在单元格中的同一张ws2
" L4"根据代码的底部部分,但它不起作用。
Sub ClickThisMacro()
Dim i As Long
Dim y As Long
Dim n As Long
Dim ws1 As Worksheet: Set ws1 = ThisWorkbook.Sheets("Report")
Dim ws2 As Worksheet: Set ws2 = Sheets.Add
Set rng1 = ws1.Range("A:A").Find("Name")
fr = rng1.Row
lr = ws1.Range("B" & Rows.Count).End(xlUp).Row
y = 2
For i = fr + 1 To lr
ws2.Cells(y, 1) = ws1.Cells(i, 1)
ws2.Cells(y, 2) = ws1.Cells(i, 2)
ws2.Cells(y, 3) = ws1.Cells(i, 3)
ws2.Cells(y, 4) = ws1.Cells(i, 4)
ws2.Cells(y, 5) = ws1.Cells(i, 18)
y = y + 1
Next i
ws2.Cells(1, 1) = "Cost centre name"
ws2.Cells(1, 2) = "Cost centre code"
ws2.Cells(1, 3) = "Phone number"
ws2.Cells(1, 4) = "User name"
ws2.Cells(1, 5) = "Amount"
LastRow = ws2.Range("A1").End(xlDown).Row
' making columns C and F numbers
ws2.Range("C2:C" & LastRow).Select
For Each xCell In Selection
xCell.Value = xCell.Value
Next xCell
With ws2.UsedRange.Columns(5)
.Replace "£", "", xlPart
.NumberFormat = "#,##0.00"
.Formula = .Value
End With
With ws2.UsedRange.Columns(8)
.Replace "£", "", xlPart
.NumberFormat = "#,##0.00"
.Formula = .Value
End With
'Pivot table
Dim mypivot As PivotTable
Dim mycache As PivotCache
Set mycache = ws2.PivotCaches.Create(xlDatabase, Range("a1").CurrentRegion)
Set mypivot = ws2.PivotTables.Add(mycache.Range("l4"), "Mypivot1")
mypivot.PivotFields("Cost centre name").Orientation = xlRowField
mypivot.PivotFields("Cost centre code").Orientation = xlColumnField
mypivot.PivotFields("Amount").Orientation = xlDataField
End Sub
答案 0 :(得分:1)
您在设置PivotCache
和PivotTable
对象的部分的代码中存在一些语法错误。
修改后的代码 (数据透视表部分)
' set the Pivot-Cache
Set mycache = ThisWorkbook.PivotCaches.Create(SourceType:=xlDatabase, SourceData:=ws2.Range("A1").CurrentRegion.Address(False, False, xlA1, xlExternal))
' set the Pivot-Table object
Set mypivot = ws2.PivotTables.Add(PivotCache:=mycache, TableDestination:=ws2.Range("L4"), TableName:="Mypivot1")
With mypivot
.PivotFields("Cost centre name").Orientation = xlRowField
.PivotFields("Cost centre code").Orientation = xlColumnField
.PivotFields("Amount").Orientation = xlDataField
End With
您应该在代码中添加一些其他修改/建议:
Find
你应该处理一个场景(即使不太可能)你找不到你想要的术语,在这种情况下如果Rng1 = Nothing
那么fr = Rng1.Row
会导致运行时错误。处理Find
代码:
Set Rng1 = ws1.Range("A:A").Find("Name")
If Not Rng1 Is Nothing Then ' confirm Find was successfull
fr = Rng1.Row
Else ' if Find fails
MsgBox "Critical Error, couldn't find 'Name' in column A", vbCritical
Exit Sub
End If
Select
和Selection
,而是可以使用完全限定的Range
对象:通过范围循环:
For Each xCell In ws2.Range("C2:C" & lr)
xCell.Value = xCell.Value
Next xCell