Question

以下是我根据用户在应用中输入的一组数字生成强力球票的代码。

num1 = ""
num2 = ""
num3 = ""
num4 = ""
num5 = ""
num6 = ""

var numString = "1325102719740829201002101968241083020081601103414208523811"
function megaNum(numString){
    numType1 = [(Math.floor(Math.random() * 6 ))];
    if (numType1 == 0){
        do{
         num1 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (num1 == 0);
        num1 = "0" + num1

    }

    if (numType1 != 0){
        do{
            digit1 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (digit1 > 6 || digit1 == 0);
        digit2 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        num1 = digit1.concat(digit2)
    }
    numType2 = [(Math.floor(Math.random() * 6 ))];
    if (numType2 == 0){
        do{
         num2 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (num2 == 0);
        num2 = "0" + num2

    }

    if (numType2 != 0){
        do{
            digit3 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (digit3 > 6 || digit3 == 0);
        digit4 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        num2 = digit3.concat(digit4)
    }

    numType3 = [(Math.floor(Math.random() * 6 ))];
    if (numType3 == 0){
        do{
         num3 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (num3 == 0);
        num3 = "0" + num3

    }

    if (numType3 != 0){
        do{
            digit5 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (digit5 > 6 || digit5 == 0);
        digit6 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        num3 = digit5.concat(digit6)
    }
    numType4 = [(Math.floor(Math.random() * 6 ))];
    if (numType4 == 0){
        do{
         num4 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (num4 == 0);
        num4 = "0" + num4

    }

    if (numType4 != 0){
        do{
            digit7 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (digit7 > 6 || digit7 == 0);
        digit8 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        num4 = digit7.concat(digit8)
    }
    numType5 = [(Math.floor(Math.random() * 6 ))];
    if (numType5 == 0){
        do{
         num5 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (num5 == 0);
        num5 = "0" + num5

    }

    if (numType5 != 0){
        do{
            digit9 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (digit9 > 6 || digit9 == 0);
        digit10 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        num5 = digit9.concat(digit10)
    }
    numType6 = [(Math.floor(Math.random() * 6 ))];
    if (numType6 == 0){
        do{
         num6 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (num6 == 0);
        num6 = "0" + num6

    }

    if (numType6 != 0){
        do{
            digit11 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (digit11 > 2 || digit11 == 0);
        do{
        digit12 = numString.split('')[(Math.floor(Math.random() * numString.length ))];
        }
        while (digit12 > 6);
        num6 = digit11.concat(digit12)
    }
    return (num1 + "-" + num2 + "-" + num3 + "-" + num4 + "-" + num5 + "-" + num6)


}

我的问题是如何设置数字1 - 5必须唯一的条件 - 不能重复？我尝试使用while循环，但陷入无限循环。我尝试了一些不同的方法，但不能让它出来正确。我知道我需要一种if语句，但不确定语法可以确保前五个数字是唯一的。

Answer 1

很难说你试图从你提供的代码中解决问题，但我想我明白你在做什么。

这并不能完全满足您的需要，但您可以使用它来重构您的代码。特别是，查看doWork函数，它是执行实际工作的函数。 getRandomNumber和checkForUniqueness函数只是帮助函数，以允许doWork以更简洁的方式执行它需要做的事情。

function getRandomNumber(ceiling) {
    // gets a random number lower than ceiling
    let retVal = 0;
    while (retVal == 0) {
        retVal = Math.floor(Math.random() * ceiling);
    }
    return retVal;
}

function checkForUniqueness(arr, num) {
    // check the previous indeces of the array to ensure uniqueness
    let retVal = true;
    if (arr.length > 0) {
        for (let i = 0; i < arr.length; ++i) {
            if (arr[i] == num) {
                retVal = false;
                break; // no need to check the rest of the numbers
            }
        }
    }
    return retVal;
}

function doWork() {
    let numbers = [];
    let num = 0;
    while(numbers.length < 5) {
        num = getRandomNumber(6);
        while (!checkForUniqueness(numbers, num)) {
            num = getRandomNumber(6);
        }
        numbers.push(num);
    }
    return numbers;
}

doWork(); // this results in an array containing [1,2,3,4,5] in a random order

基本上，您需要遵循的逻辑是：

// get a random number
// make sure the array (or whatever structure you're using) doesn't 
//   already contain that number
// insert that number

在js中，生成一个强力球票，不需要重复数字

1 个答案: