Question

我查看了每个可能的论坛和问题页面，仍然无法理解为什么我的sql搜索没有返回任何值。它是用PHP脚本编写的，用于搜索用户在HTML页面上输入的名称并返回数据库中的所有列。

请注意，我对学习PHP和SQl相当陌生，所以请不要讨厌，如果这只是我愚蠢的哈哈。

提前致谢，克里斯

<!DOCTYPE html>
<html>
    <body>
        <?php
            $ServerName = "****";
            $LogInUN = "*****";
            $LogInPW = "******";
            $DBName = "********";

            $Connection = mysqli_connect($ServerName, $LogInUN, $LogInPW, $DBName);

            if(!$Connection){
              die("<p>Connection error!</p>" . mysqli_connect_error());
            }

            $Name = mysqli_real_escape_string($Connection, $_POST['Name']);

            $Query = "SELECT Firstname FROM Students WHERE Firstname LIKE '%{%Name}%'";

            $result = $Connection->query($Query);

                        echo $result;
                        echo $Name;

        ?>
    </body>
</html>

Answer 1

使用$ Name

$Query = "SELECT Firstname FROM Students WHERE Firstname LIKE '%{$Name}%'";

在$result = $Connection->query($Query);行写下行

之后

while($row = mysqli_fetch_assoc($result)) {
                       echo $row["Firstname"];
                        echo $Name;
}

删除$result = $Connection->query($Query);并使用

$result = mysqli_query($Connection, $Query);

Answer 2

$ Query =＆＃34; SELECT Firstname FROM Students WHERE First＆LIKE＆＃39;％{％Name}％＆＃39;＆＃34 ;; 用这个 $ Query =＆＃34; SELECT Firstname FROM Students WHERE LIKE LIKE＆＃39;％{$ Name}％＆＃39;＆＃34;;

SQL搜索没有返回任何输出？

2 个答案: