Question

我想通过codeignitor获取mysql代码的以下结果。它为tbl_user_unavailability表中提供的时间帧提供非等于id（tbl_user）

MySql代码

SELECT tbl_user.id

FROM  tbl_user

INNER JOIN tbl_user_unavailability

on tbl_user_unavailability.user_id <> tbl_user.id

WHERE '2018-02-02' BETWEEN begin_date AND end_date;

结果

22

25

find the mysql code result screenshot here

通过codeignitor获得此结果，我使用了以下代码

控制器代码

公共功能测试（）{

     $current_date = '2018-02-02';

     $available_users = $this->mod_users->test_test($current_date);
     $data['available_users'] = $available_users;

     //to test the result array
     //var_dump($available_users);die();

     $data['related_view']='user_unavailable_new';
     $this->load->view('template', $data); 
}

型号代码

public function test_test（$ current_date）{

$this->load->database();
$this->db->select('*');    
$this->db->join('tbl_user_unavailability',  'tbl_user_unavailability.user_id <> tbl_user.id','inner');    
$this->db->where("'$current_date' BETWEEN  'tbl_user_unavailability.begin_date' AND 'tbl_user_unavailability.end_date'");
$query =  $this->db->get($this->table);
return $query->result_array();

}

结果

not showing anything

I have tested it with var_dump($available_users);die();

It shows empty array

通过内部联接使用Codeigniter

0 个答案: