Question

我的日期时间导出是“CAST（0x0000987C00000000 AS DateTime）”但是当我想将它恢复到datetime.It是一个NULL值。我怎样才能再次进入日期时间。

Answer 1

看起来像SQL Server datetime格式。在内部，它存储为2个整数，前4个字节是自1900年1月1日以来的天数，第2个字节是自午夜以来的刻度数（每个刻度为1/300秒）。

如果您需要在MySQL中使用它，那么

SELECT 
      CAST(
          '1900-01-01 00:00:00' + 
          INTERVAL CAST(CONV(substr(HEX(BinaryData),1,8), 16, 10)  AS SIGNED) DAY +
          INTERVAL CAST(CONV(substr(HEX(BinaryData),9,8), 16, 10)  AS SIGNED)* 10000/3 MICROSECOND
      AS DATETIME) AS converted_datetime
FROM
(
SELECT 0x0000987C00000000 AS BinaryData
UNION ALL
SELECT 0x00009E85013711EE AS BinaryData
) d

返回

converted_datetime
--------------------------
2006-11-17 00:00:00
2011-02-09 18:52:34.286667

（感谢Ted Hopp在分割二进制数据时the solution）

Answer 2

并没有真正添加任何未说明的内容，但我使用它来从上面的代码创建一个MySql函数。然后我可以使用RegEx查找和替换（在Notepad ++中）用sp_ConvertSQLServerDate（0xblahblahblah）替换CAST（0xblahblahblah AS DATETIME）。

create function sp_ConvertSQLServerDate(dttm binary(16))
returns datetime
return CAST(
      '1900-01-01 00:00:00' + 
      INTERVAL CAST(CONV(substr(HEX(dttm),1,8), 16, 10)  AS SIGNED) DAY +
      INTERVAL CAST(CONV(substr(HEX(dttm),9,8), 16, 10)  AS SIGNED)* 10000/3 MICROSECOND
AS DATETIME);

Answer 3

这与 PostgreSQL ：

的选择语句相同

SELECT '1900-01-01 00:00:00'::date +
    (('x'||substring(x::text,3,8))::bit(32)::int::text||'days')::interval +
    ((('x'||substring(x::text,11,8))::bit(32)::int /300)::text||' seconds')::interval
FROM (VALUES 
    ('0x00009fff00e24076'),
    ('0x00009ff10072d366'),
    ('0x00009ff10072ce3a'),
    ('0x00009ff10072c5e2'),
    ('0x00009ff10072bc3c'))  as x(x);

PostgreSQL位（32）值必须以'x'值而不是0开始。

Answer 4

这是我做过的Java程序。

程序扫描给定文件（在下面的代码中更改名称）

CAST(0x... AS DateTime)

并将其替换为各自的

CAST('yyyy-MM-dd HH:mm:ss.SSS' AS DateTime)

例如，考虑到SELECT CAST (0x00009CEF00A25634 as datetime)返回2009-12-30 09:51:03.000，程序会扫描文件CAST(0x00009CEF00A25634 AS DateTime)并将其替换为CAST('2009-12-30 09:51:03.000' AS DateTime)。

我用它将SQL Server生成的脚本转换为H2嵌入式数据库可以理解的东西。

尽管它对我来说很好，我建议你在使用实际数据之前检查它（只是运行一些测试数据并查看）。

import java.io.*;
import java.text.*;
import java.util.*;
import java.util.regex.*;

public class ReplaceHexDate {

    public static void main(String[] args) throws Exception {
        String inputFile = "C:/input.sql";
        String inputEncoding = "UTF-8";
        String outputFile = "C:/input-replaced.sql";
        String outputEncoding = "UTF-8";

        BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(inputFile), inputEncoding));
        BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(outputFile), outputEncoding));

        String line;
        while ((line = br.readLine()) != null) {
            if (line.indexOf("CAST(0x") > -1) {
                bw.write(replaceHexWithDate(line));
            } else {
                bw.write(line);
            }
            bw.newLine();
        }
        br.close();
        bw.flush();
        bw.close();
    }

    private static String replaceHexWithDate(String sqlLine) throws ParseException {
        Pattern castPattern = Pattern.compile("(CAST\\()(0x[A-Fa-f0-9]{16})( AS DateTime\\))");
        Matcher m = castPattern.matcher(sqlLine);
        while (m.find()) {
            String s = m.group(2);
            sqlLine = sqlLine.replace(s, "'"+sqlServerHexToSqlDate(s)+"'");
        }
        return sqlLine;
    }

    public static String sqlServerHexToSqlDate(String hexString) throws ParseException {
        String hexNumber = hexString.substring(2); // removes the leading 0x
        String dateHex = hexNumber.substring(0, 8);
        String timeHex = hexNumber.substring(8, 16);

        long daysToAdd = Long.parseLong(dateHex, 16);
        long millisToAdd = (long) (Long.parseLong(timeHex, 16) *10/3);

        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");

        Calendar startingCal = Calendar.getInstance();
        String startingDate = "1900-01-01 00:00:00.000";
        startingCal.setTime(sdf.parse(startingDate));

        Calendar convertedCal = Calendar.getInstance();
        convertedCal.setTime(sdf.parse(startingDate));
        convertedCal.add(Calendar.DATE, (int) daysToAdd);
        convertedCal.setTimeInMillis(convertedCal.getTimeInMillis() + millisToAdd);

        return sdf.format(convertedCal.getTime());
    }
}

Answer 5

使用notepad ++ regex替换

cast[(]0x([0-9A-F]{16}) As DateTime[)]

CAST('1900-01-01 00:00:00' + INTERVAL CAST(CONV(substr(HEX( 0x\1 ),1,8), 16, 10)  AS SIGNED) DAY + INTERVAL CAST(CONV(substr(HEX( 0x\1 ),9,8), 16, 10)  AS SIGNED)* 10000/3 MICROSECOND AS DATETIME)

这将取代

CAST(0x0000A26900F939A8 AS DateTime)

到

CAST('1900-01-01 00:00:00' + INTERVAL CAST(CONV(substr(HEX( 0x0000A26900F939A8 ),1,8), 16, 10)  AS SIGNED) DAY + INTERVAL CAST(CONV(substr(HEX( 0x0000A26900F939A8 ),9,8), 16, 10)  AS SIGNED)* 10000/3 MICROSECOND AS DATETIME),

Answer 6

日期和日期时间的MSSQL十六进制代码不同。

对于像0x00000000这样的日期，你可以使用这个postgres函数：

CREATE FUNCTION convertedata(text) RETURNS timestamp without time zone
as $$ SELECT '0001-01-01 00:00:00'::date + (('x'||
(regexp_replace(
substring($1::text,3,8)::text,
 '(\w\w)(\w\w)(\w\w)(\w\w)',
 '\4\3\2\1'))::text
)::bit(32)::int::text||'days')::interval $$
LANGUAGE SQL;

然后尝试

select convertedata('0x0E360B00')

Answer 7

对于那些在C＃中寻找解决方案的人。例如，在读取脚本化数据库数据时。

        string pattern = @"CAST\(0x(\w{8})(\w{8}) AS DateTime\)";
        Regex r = new Regex(pattern);
        Match m = r.Match(hex);            

        int d = System.Convert.ToInt32("0x" + m.Groups[1].Value, 16);
        int t = System.Convert.ToInt32("0x" + m.Groups[2].Value, 16);

        DateTime converted = new DateTime(1900, 1, 1).AddDays(d).AddSeconds(t/300);

这里我使用了正则表达式，因为我的输入采用以下格式＆＃34; CAST（0x0000A53E00E1A17B AS DateTime）＆＃34;，但您可以使用SubString（）或其他任何方法来获取DateTime字符串。

如何将十六进制转换为varchar（datetime）？

7 个答案: