您好我想知道我的代码有什么问题
pizza = "2.99"
puts "hello what would you like to buy?"
food_type = gets.chomp.downcase
puts "How many?"
food_amount = gets.chomp!
puts #{food_amount.to_i * food_type.to_f}
答案 0 :(得分：2)
要做这样的事情，你应该用哈希值存储不同类型的食物，并使用{ "food type" => cost of food }（例如，{ 'pizza' => 9.99, 'soda' => 2.99, 'breadsticks' => 1.50 }）注意价格已经是浮点数，因此以后不需要转换
然后当你循环时，你可以将他们购买的东西保存在另一个散列{ 'food type' => quantity }中，数量为整数。然后，当他们完成选择项目时，你会遍历“购物车”并将所有内容相乘：
menu = { 'pizza' => 9.99, 'soda' => 2.99, 'breadsticks' => 1.50 }
cart = Hash.new(0)
begin
puts "hello what would you like to buy?"
food_type = gets.chomp.downcase
puts "How many?"
quantity = gets.to_i
cart[food_type] += quantity
puts "Want Anything Else?"
buy_more = (gets.chomp == "yes")
end while buy_more
puts "you're buying:"
cart.each do |food_type, quantity|
puts "#{quantity} of #{food_type} for #{quantity * menu.fetch(food_type, 0)}"
end
示例运行：
hello what would you like to buy?
soda
How many?
2
Want Anything Else?
yes
hello what would you like to buy?
pizza
How many?
5
Want Anything Else?
yes
hello what would you like to buy?
breadsticks
How many?
1
Want Anything Else?
yes
hello what would you like to buy?
something else
How many?
10
Want Anything Else?
no
you're buying:
2 of soda for 5.98
5 of pizza for 49.95
1 of breadsticks for 1.5
10 of something else for 0
了解有关Hash in the docs的更多信息，该信息应该包含足够的信息，让您了解我尚未添加的repl部分，并决定如何处理无效条目（例如我输入时）其他'为食物类型）。此示例仅将其视为无效的有效项目。