Question

首先关闭apoligies，我对VBA for Access中的编码完全不熟悉，因此可能存在很多错误。但无论如何，我在第一个名字和中间名词时遇到了一些问题。目前，名称被格式化为[lastName，firstName middleInitial]中的字符串我有3个文本框，标注为lastName firstName和middleInitial。下面的代码应该做的是将该字符串分成三个适当的框，但它挂在第一个名字上，它不知道如何停留在空间或者它切断了几个字符，中间初始它只有在有中间的初始值时才有效，但如果找不到则会抛出错误。我一直在试图弄清楚我的头发，因此我已经到了一个指导，我在这里问。

非常感谢！

Private Sub cbxMbr_AfterUpdate()

    If Not Me.opgMngRoster.Value = 1 Then
        'Member's Last Name
        Dim lastName As String
        lastName = Left(cbxMbr.Text, (InStr(1, cbxMbr.Text, ",") - 1))
        Me.txtLastName.Value = lastName

        'Member's First Name
        Dim firstName As String
        firstName = Mid(cbxMbr.Text, InStr(1, cbxMbr.Text, " "), (Len(cbxMbr.Text) - InStr(1, cbxMbr.Text, " ")))
        Me.txtFirstName.Value = firstName

        'Member's Middle Initial
        Dim midName As String
        midName = Mid(cbxMbr.Text, InStr(InStr(1, cbxMbr.Text, " ") + 1, cbxMbr.Text, " "))

        If midName = vbNullString Then
            Me.txtMidInit.Value = " "
        Else
            Me.txtMidInit.Value = midName
        'DoCmd.RunSQL "SELECT MEMBER ROSTER WHERE "
        End If
    End If

End Sub

Answer 1

您可以使用拆分：

' "Duck, Donald D."
' "Duck, Donald"

Me!txtLastName.Value = Split(Me!cbxMbr.Value, ",")(0)
' Duck

Me!txtFirstName.Value = Split(Trim(Split(Me!cbxMbr.Value, ",")(1)), " ")(0)
' Donald

Me.txtMidtInit.Value = Split(Trim(Split(Me!cbxMbr.Value, ",")(1)) & " ", " ")(1)
 ' D. or zero-length string.

在VBA Access

1 个答案: